规则无法按预期工作的Firebase电子邮件身份验证

本文介绍了规则无法按预期工作的Firebase电子邮件身份验证的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述 在管理屏幕中，我同时使用电子邮件认证和匿名登录。 数据只有一个节点 - Hello：World 我的规则是 rules：{$ b $.read：auth！= null， // \".read：true， .write：true } } 如果用户没有使用上述规则登录，那么您将获得读取失败：权限被拒绝这样很好。 如果一个匿名用户登录，那么我可以看到值{Hello = World} 到目前为止。 如果我使用电子邮件登录用户我得到一个错误：FirebaseError：权限被拒绝 onAuthenticate确实触发，我得到：用户ID：3c6ce912-a05a-49ed-ae68-8ec97d022303 ，Provider：password 完整的代码如下。我在做什么错了？ import com.firebase.client.AuthData; import com.firebase.client.DataSnapshot; import com.firebase.client.Firebase; import com.firebase.client.FirebaseError; import com.firebase.client.ValueEventListener; import java.io.IOException; import java.util.logging.Level; import java.util.logging.Logger; public class FirebaseTest { Firebase ref = new Firebase（https：//< FIREBASE NAME> .firebaseio.com /）; public FirebaseTest（）{ // logonAnonymous（）; //作品 logonEmail（）; //权限被拒绝 showValues（）; 尝试{ System.out.println（等待输入）; System.in.read（）; catch（IOException ex）{ Logger.getLogger（NewClass.class.getName（））.log（Level.SEVERE，null，ex）; private void logonAnonymous（）{ ref.authAnonymously（new Firebase.AuthResultHandler（）{ @Override public void onAuthenticated（AuthData authData）{ //我们已经使用您的Firebase应用程序对此会话进行了身份验证 System.out.println（User ID：+ authData.getUid（）+，Provider： + $ authData.getProvider（））; } $ b $ @覆盖 public void onAuthenticationError（firebaseError firebaseError）{ //出现错误系统.out.println（Anon user auth error+ firebaseError.toString（））; } }）; private void logonEmail（）{ ref.authWithPassword（[email protected]，secret，new Firebase.AuthResultHandler（）{ @Override $ b $ public void onAuthenticated（AuthData authData）{ System.out.println（User ID：+ authData.getUid（）+，Provider：+ authData.getProvider ））; } @Override public void onAuthenticationError（FirebaseError firebaseError）{ //出现错误} } ）; $ b $ public void showValues（）{ ref.addValueEventListener（new ValueEventListener（）{ @Override public void onDataChange DataSnapshot快照）{ System.out.println（value - + snapshot.getValue（））; } $ b @覆盖 public void onCancelled（FirebaseError firebaseError）{ System.out.println（The read failed：+ firebaseError.getMessage（））; } }）; $ / code> } 解决方案我很肯定你只是看到电子邮件+密码认证异步发生的效果。 序列： logonEmail（）; showValues（）; 身份验证在 showValues（） code $ c>执行。 异步排序的解决方案很简单，但最初非常不直观：您需要确保 showValues（）只在认证成功后执行 一个简单的方法： private void logonEmail（）{ ref.authWithPassword（[email protected]，secret，新的Firebase。 AuthResultHandler（）{ @Override public void onAuthenticated（AuthData authData）{ System.out.println（User ID：+ authData.getUid（）+，Provider：+ authData.getProvider（））; //用户已被认证，所以我们现在可以安全地调用showValue（） showValues（）; } @Override public void onAuthenticationError（firebaseError firebaseError）{ //有一个错误} }）; } In the management screen I have both email auth and anonymous login enabled.The data has only one node - Hello: "World"The rule that I have is { "rules": { ".read": "auth != null", //".read": true, ".write": true }}If the user is NOT logged in with the above rule then you get The read failed: Permission deniedThat's all good.If a anonymous user is logged in then I can see the value "{Hello=World"}Works so far.If i log in with a email user the I get an error :FirebaseError: Permission deniedThe onAuthenticate does trigger and I get :User ID: 3c6ce912-a05a-49ed-ae68-8ec97d022303, Provider: passwordThe complete code is below. What am I doing wrong?import com.firebase.client.AuthData;import com.firebase.client.DataSnapshot;import com.firebase.client.Firebase;import com.firebase.client.FirebaseError;import com.firebase.client.ValueEventListener;import java.io.IOException;import java.util.logging.Level;import java.util.logging.Logger;public class FirebaseTest {Firebase ref = new Firebase("https://<FIREBASE NAME>.firebaseio.com/");public FirebaseTest() { //logonAnonymous(); //works logonEmail(); //permission denied showValues(); try { System.out.println("Waiting for input"); System.in.read(); } catch (IOException ex) { Logger.getLogger(NewClass.class.getName()).log(Level.SEVERE, null, ex); }}private void logonAnonymous() { ref.authAnonymously(new Firebase.AuthResultHandler() { @Override public void onAuthenticated(AuthData authData) { // we've authenticated this session with your Firebase app System.out.println("User ID: " + authData.getUid() + ", Provider: " + authData.getProvider()); } @Override public void onAuthenticationError(FirebaseError firebaseError) { // there was an error System.out.println("Anon user auth error " + firebaseError.toString()); } });}private void logonEmail() { ref.authWithPassword("[email protected]", "secret", new Firebase.AuthResultHandler() { @Override public void onAuthenticated(AuthData authData) { System.out.println("User ID: " + authData.getUid() + ", Provider: " + authData.getProvider()); } @Override public void onAuthenticationError(FirebaseError firebaseError) { // there was an error } });}public void showValues() { ref.addValueEventListener(new ValueEventListener() { @Override public void onDataChange(DataSnapshot snapshot) { System.out.println( " value -" + snapshot.getValue()); } @Override public void onCancelled(FirebaseError firebaseError) { System.out.println("The read failed: " + firebaseError.getMessage()); } });}} 解决方案 I'm pretty sure you're just seeing the effects of the fact that email+password authentication happens asynchronously.In this sequence:logonEmail();showValues(); The authentication will not yet have finished by the time showValues() executes.The solution for asynchronous ordering is simple, but initially very unintuitive: you need to ensure that showValues() only executes after the authentication has succeeded.A simple way to do this:private void logonEmail() { ref.authWithPassword("[email protected]", "secret", new Firebase.AuthResultHandler() { @Override public void onAuthenticated(AuthData authData) { System.out.println("User ID: " + authData.getUid() + ", Provider: " + authData.getProvider()); // The user has been authenticated, so we can now safely call showValue() showValues(); } @Override public void onAuthenticationError(FirebaseError firebaseError) { // there was an error } });} 这篇关于规则无法按预期工作的Firebase电子邮件身份验证的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！