将函数返回的内容从"std :: vector< QString>"转换为"QVariant"

问题描述

我正在研究基于QT的应用程序.我的课程之一是 QAbstractTableModel .数据函数的返回类型为 QVariant (联合).但是我要返回自定义类型std::vector<QString>

I am working on a QT based application.One of of my class is a child class of QAbstractTableModel. The data function has a return type of QVariant(Union).But i want to return a custom type std::vector<QString>

有关 Q_DECLARE_METATYPE(); 的知识QVariant可用的类型.

Came to know about Q_DECLARE_METATYPE(); It makes new types available to QVariant.

-测试案例代码-

#include <QApplication>
#include <QMetaType>
#include <vector>
#include<QVariant>


Q_DECLARE_METATYPE(std::vector<QString>);

QVariant data(int role)
{
    std::vector<QString> test1;
    test1.push_back("Dtd");
    test1.push_back("Dtd");
    return test1;
}

int main(int argc, char *argv[])
{

    QApplication app(argc, argv);
     data(1);
    return app.exec();
}

我收到此错误

我错过了一些东西.请帮助

I am missing out something.Please Help

推荐答案

即使您声明了新的元类型，编译器仍然会看到您正在尝试返回声明了QVariant的std::vector.试试这个:

Even if you've declared a new metatype, the compiler still sees you're trying to return a std::vector where you've declared returning a QVariant. Try this:

QVariant data(int role)
{
    std::vector<QString> test1;
    test1.push_back("Dtd");
    test1.push_back("Dtd");
    QVariant var;
    var.setValue(test1);
    return var;
}

这篇关于将函数返回的内容从"std :: vector< QString>"转换为"QVariant"的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！