如何在CanJS中使用Defer

问题描述

Featoff = can.Model.extend("featoff",{
        findAll: {
        url: '/api.php/specialoffers?',
        type: 'GET',
        data: { max : 10 , pid : 977 , sid : 5934 }
        }
      }, {});

Feat = can.Control({ init: function()
 { var that = this; can.view('images/js/mn/temps/featured.ejs', featoff.findAll({}).then(function(d) 
{ return { offerdata : d, secTitle : that.element.data('title') }; })).done(function(frag) 
{ that.element.html(frag); }) }}); 

我正在使用新的Feat()来调用它；

I am calling this using new Feat();

这现在正在工作.因此，现在我想在findAll中使用相同的Feat控件和不同的参数集重复使用，我该怎么做?使用什么方法以及如何使用?我也可以针对相同的??推迟或覆盖can.view吗?

this is working now. So now I wanna reuse the same Feat control with different set of parameters in the findAll, How can i do so? What method to use and how to use?? also can I also defer or override the can.view for the same ??

我还可以拥有一个Base控制器，并继续覆盖参数吗?

Can I also have a single Base controller and just keep overriding the parameters?

推荐答案

要覆盖视图，可以扩展Feat对象FeatExtended = Feat.extend{并在init方法中使用其他视图.

To override the view you can extend your Feat object FeatExtended = Feat.extend{ and use a different view in the init method.

您也可以在调用new Feat({view : MY_VIEW})时提供参数.根据此处的说明，将选项对象传递给init().

You can also give parameters when calling new Feat({view : MY_VIEW}). An options object is passed to init() as describe here.

对于您的findAll问题，您应该将findAll定义为中描述的方法.文档

For you findAll question, you should define findAll as a method as describe in the documentation

希望有帮助！

例如:您可以传递一个params对象，该对象定义要在URL中添加的选项以及HTTP调用的方法

For example : you can pass a params object defining an option to be added in URL and the method of the HTTP call

Featoff = can.Model.extend({
  findAll : function(params){
    return $.ajax({
      url: '/api.php/specialoffers?' + params.myoption,
      type: params.method,
      dataType: 'json'})
  }
},{})

这篇关于如何在CanJS中使用Defer的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！