问题描述
我是一个初学者，一直在查看，但我在这里无法理解问题。这很简单，如果用户输入y，则应该打印此内容，尽管我在IF answer == y
I am a total beginner and have been looking at http://en.wikibooks.org/wiki/Python_Programming/Conditional_Statements but I can not understand the problem here. It is pretty simple, if the user enters y it should print this will do the calculation although I get a syntax error on IF answer=="y"
answer = str(input("Is the information correct? Enter Y for yes or N for no"))
proceed="y" or "Y"
If answer==proceed:
print("this will do the calculation"):
else:
exit()
推荐答案
即使您修复了大小写错误的 if 和代码中的缩进，它也不会不能按您预期的那样工作。要对照一组字符串检查一个字符串，请在中使用。这是您的操作方式（请注意， if 都是小写，并且 if 块中的代码是
Even once you fixed the mis-cased if and improper indentation in your code, it wouldn't work as you probably expected. To check a string against a set of strings, use in. Here's how you'd do it (and note that if is all lowercase and that the code within the if block is indented one level).
一种方法：
if answer in ['y', 'Y', 'yes', 'Yes', 'YES']:
print("this will do the calculation")
另一个：
if answer.lower() in ['y', 'yes']:
print("this will do the calculation")
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