本文介绍了如何让网络摄像机流成C#?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我用AForge库,使这个小程序,这显示了一个摄像头实时输入到一个PictureBox。
I've used AForge library to make this little program, that shows live feed from a webcam into a PictureBox.
private FilterInfoCollection VideoCaptureDevices;
private VideoCaptureDevice FinalVideoDevice;
private void Form1_Load(object sender, EventArgs e)
{
VideoCaptureDevices = new FilterInfoCollection(FilterCategory.VideoInputDevice);
try
{
foreach (FilterInfo VidCapDev in VideoCaptureDevices)
{
comboBox1.Items.Add(VidCapDev.Name);
comboBox1.SelectedIndex = 0;
}
FinalVideoDevice = new VideoCaptureDevice(VideoCaptureDevices[comboBox1.SelectedIndex].MonikerString);
FinalVideoDevice.NewFrame += new NewFrameEventHandler(FinalVideoDevice_NewFrame);
FinalVideoDevice.Start();
}
catch
{
MessageBox.Show("No camera found. Please connect your camera and click RESET.");
}
}
//////////////////////////////////////////////////////////////////////////////////////////
void FinalVideoDevice_NewFrame(object sender, NewFrameEventArgs e)
{
try
{
pictureBox1.Image = (Bitmap)e.Frame.Clone();
}
catch { }
}
但我也需要从IP摄像机获取流。任何想法将是最好的方式得到它?
But I also need to get a stream from an IP camera. Any ideas what would be the best way to get it?
谢谢!
推荐答案
从同一AForge.net解决了它与MJPEGStream:)
Solved it with MJPEGStream from the same AForge.net :)
MJPEGStream stream = new MJPEGStream("http://192.168.2.5:8080/videofeed");
stream.NewFrame += new NewFrameEventHandler(video_NewFrame);
stream.Start();
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