点击单选按钮可以刷新div吗？

问题描述

有没有可能刷新div上的一个单选按钮，在该div内呈现？

我有这种情况;

使用jQuery，我需要刷新单选按钮上的div。单选按钮存在于需要刷新的特定div中。

>

到目前为止所做的所有研究，我看到的webPages / forums，他们都有一些应该刷新的div外的按钮示例。

我有类似的东西：

 < div class =abc> 
 
< ul class =typeA> 
< li>< input name =regType34onclick =javascript：loadRegister（'34'，$（this）.attr（'data-title'））; value =REGtype =radioid =34_1class =MyStyledata-title =regchecked =checked> 
< label for =34_1style =background-position：0px -67px;>注册< / label>< / li> 
< li>< input name =regType34onclick =javascript：loadGraph（'34'，$（this）.attr（'data-title'））; value =GRAtype =radioid =34_2class =MyStyledata-title =gra> < label for =34_2>图< / label>< / li> 
< / ul> 
< / div> 
  

当用户点击regType34时，是否有可能刷新整个divabc？

刷新意味着重新加载div的内容

（$ {
$（input [name = regType34]）。click（function（）{
$（＃abc） .html（你想在div刷新时显示的html）;
}）

Is it possible to refresh a div on a radio button click presented within that div?

I have this scenario;

Using jQuery,I need to refresh a div on a radio button click.And the radio button is present in that particular div that I need to be refreshed.

All the research that I have done so far, webPages/forums I've seen, they all have examples of buttons outside the div that is supposed to be refreshed.

I have something like:

<div class="abc">

    <ul class="typeA">
        <li><input name="regType34" onclick="javascript:loadRegister('34',$(this).attr('data-title'));" value="REG" type="radio" id="34_1" class="MyStyle" data-title="reg"  checked="checked">
        <label for="34_1" style="background-position: 0px -67px;">Register</label></li>
        <li><input name="regType34" onclick="javascript:loadGraph('34',$(this).attr('data-title'));" value="GRA" type="radio" id="34_2" class="MyStyle" data-title="gra"> <label for="34_2">Graph</label></li>
    </ul>
</div>

Is it possible that when user click on "regType34", complete div "abc" will get refreshed?

Refresh means reloading of the content of div

解决方案

Try this :
    $("input[name=regType34]").click(function(){
    $("#abc").html("html that you want to show on div refresh");
    })

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