在Python中自动读取配置值

问题描述

我想将Python中的配置文件完全读入数据结构，而无需明确地获取每个值。这样做的原因是我打算以编程方式修改这些值（例如，我有一个变量，说我想将 [Foo] Bar = 1 修改为是 [Foo] Bar = 2 ），目的是根据我的更改编写新的配置文件。

I would like to read a configuration file in Python completely into a data structure without explicitly 'getting' each value. The reason for doing so is that I intend to modify these values programatically (for instance, I'll have a variable that says I want to modify [Foo] Bar = 1 to be [Foo] Bar = 2), with the intention of writing a new configuration file based on my changes.

目前，我正在手工读取所有值：

At present, I'm reading all the values by hand:

parser = SafeConfigParser()
parser.read(cfgFile)
foo_bar1 = int(parser.get('Foo', 'Bar1'))
foo_bar2 = int(parser.get('Foo', 'Bar2'))

我很想拥有（在Google方面找不到很多）是一种将它们读入列表的方法，可以很容易地识别它们，以便我可以将该值从列表中拉出并更改它。

What I would love to have (didn't find much Google-wise) is a method to read them into a list, have them be identified easily so that I can pull that value out of the list and change it.

本质上将其引用为（或类似）：

Essentially referencing it as (or similarly to):

config_values = parser.read(cfgFile)
foo_bar1      = config_values('Foo.bar1')

推荐答案

import sys
from ConfigParser import SafeConfigParser

parser = SafeConfigParser()
parser.readfp(sys.stdin)

config = dict((section, dict((option, parser.get(section, option))
                             for option in parser.options(section)))
              for section in parser.sections())
print config

输入

Input

[a]
b = 1
c = 2
[d]
e = 3

Output

{'a': {'c': '2', 'b': '1'}, 'd': {'e': '3'}}

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