问题描述
我有这个测试代码使用Blowfish（openssl / blowfish.h）加密，然后解密一个字符串。但是当它再次出来，它没有被正确解密。任何人都可以告诉我为什么要？
I have this piece of test code that uses Blowfish (openssl/blowfish.h) to encrypt, then decrypt a string. But when it comes out again, it hasn't been decrypted properly. Can anyone tell me why please?
（从）
#include <stdlib.h>
#include <cstdio>
#include <string.h>
#include <iostream>
using namespace std;
int main(int argc, char **argv)
{
// blowfish key
const char *key = "h&6^5fVghasV_Fte";
BF_KEY bfKey;
BF_set_key(&bfKey, strlen(key), (const unsigned char*)key);
// encrypt
const unsigned char *inStr = (const unsigned char *)"hello world\0";
unsigned char *outStr = (unsigned char *)malloc(sizeof(unsigned char) * 100);
BF_ecb_encrypt(inStr, outStr, &bfKey, BF_ENCRYPT);
// decrypt
unsigned char buf[100];
BF_ecb_encrypt((const unsigned char*)outStr, buf, &bfKey, BF_DECRYPT);
std::cout << "decrypted: " << buf << "\n";
free(outStr);
return 0;
}
输入：Hello World
Input: "Hello World"
输出：hellowo4 \Z
Output: "hello wo4�\Z��"
推荐答案
Blowfish在64位块上运行：即8个字节的倍数。 BF_ecb_ *处理单个这样的块。这是你的字符串的前8个字符。其余的被BF_ecb_ *忽略。如果你想要加密更长的时间，如果你真的很高兴使用ECB模式，或使用类似BF_ofb _ *的东西，应用BF_ecb_ *一个块接着一个循环。
Blowfish operates on 64-bit blocks: that is, multiples of 8 bytes. BF_ecb_* processes a single such block. That's the first 8 characters of your string. The rest is ignored by BF_ecb_*. If you want to encrypt something longer, apply BF_ecb_* to one block after another in a loop if you're really happy to use the ECB mode, or use something like BF_ofb_*.
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