本文介绍了对于pd.interval,Pandas.Series.dtype.kind为None的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
测试代码:
s = pd.Series(pd.array([pd.Interval(0,1.2), pd.Interval(5,123)]))
s.dtype
s.dtype.kind is None
>>> interval[float64]
>>> True
是一些错误还是故意制作的?如果是后者-是出于什么原因?
Is it some bug or made intentionally? If latter - for what reason?
推荐答案
之所以显示为None
的原因仅仅是因为IntervalDtype
的实现明确设置kind = None
.这可能应该更新为'O'
,尽管此处需要谨慎,因为这会导致意想不到的副作用,例如这将导致is_string_dtype
返回True
(请参见此处).
The reason this is appearing as None
is simply because the implementation of IntervalDtype
explicitly sets kind = None
. This should probably be updated to 'O'
, though some care is needed here as it will result in unintended side effects, e.g. this would cause is_string_dtype
to return True
(see here).
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