问题描述
我已经看到引用 showS 技巧来构建字符串（例如，在），但我从来没有见过这么好的描述。
I have seen references to the showS trick to build strings (e.g., in this discussion), but I have never seen a good description of it.
什么是the showS trick？
What is the showS trick?
推荐答案
在标准库中，定义了 ShowS as：
In the standard library, ShowS is defined as:
type ShowS = String -> String
这是。
诀窍是一个字符串 xs 被函数表示为 ShowS 其他列表：（xs ++）。这允许有效的级联，避免了嵌套左关联级联（即（（as ++ bs）++ cs）++ ds ）的问题。例如：
This is a difference list.The trick is that a string xs is represented as a ShowS by the function that prepends it to any other list: (xs ++). This allows efficient concatenation, avoiding the problems of nested left-associative concatenation (i.e. ((as ++ bs) ++ cs) ++ ds). For example:
hello = ("hello" ++)
world = ("world" ++)
-- We can "concatenate" ShowS values simply by composing them:
helloworld = hello . world
-- and turn them into Strings by passing them an empty list:
helloworld' = helloworld ""
它被称为 ShowS ，因为它用于执行标准 Show > typeclass允许高效的 show 大型深度嵌套结构;以及 show ，您可以实现 showsPrec ，其类型为：
It's called ShowS because it's used in the implementation of the standard Show typeclass to allow efficient showing of large, deeply-nested structures; as well as show, you can implement showsPrec, which has the type:
showsPrec :: (Show a) => Int -> a -> ShowS
这允许处理运算符优先级，并返回一个 ShowS 值。标准实例实现这个而不是 show 来提高效率; show a 然后用它来定义，如 showsPrec 0 a。 （这个默认定义在 Show typeclass本身中，所以你可以为一个完整的实例实现 showsPrec ）
This allows handling of operator precedence, and returns a ShowS value. The standard instances implement this instead of show for efficiency; show a is then defined in terms of it, as showsPrec 0 a "". (This default definition is in the Show typeclass itself, so you can just implement showsPrec for a complete instance.)
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