本文介绍了返回使用JsonResult的ActionFilter上一个ActionResult在控制器的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我要回以不同的格式(的JavaScript / XML / JSON / HTML)使用ActionFilter的控制器的模型(数据)。下面是我在哪里至今:
I want to return the Model (data) of a controller in different formats (JavaScript/XML/JSON/HTML) using ActionFilter's. Here's where I'm at so far:
该ActionFilter:
The ActionFilter:
public class ResultFormatAttribute : ActionFilterAttribute, IResultFilter
{
void IResultFilter.OnResultExecuting(ResultExecutingContext context)
{
var viewResult = context.Result as ViewResult;
if (viewResult == null) return;
context.Result = new JsonResult { Data = viewResult.ViewData.Model };
}
}
而它的实现:
[ResultFormat]
public ActionResult Entries(String format)
{
var dc = new Models.WeblogDataContext();
var entries = dc.WeblogEntries.Select(e => e);
return View(entries);
}
的 OnResultExecuting
方法被调用,但我没有得到的模型(数据)返回,并格式化为一个JSON对象。我刚才控制器呈现视图。
更新:我达林季米特洛夫的回答的建议,this问题。
The OnResultExecuting
method gets called, but I am not getting the Model (data) returned and formatted as a JSON object. My controller just renders the View.
Update: I am following the suggestion of Darin Dimitrov's answer to this question.
推荐答案
这就是我一直在寻找:
public class ResultFormatAttribute : ActionFilterAttribute, IActionFilter
{
void IActionFilter.OnActionExecuted(ActionExecutedContext context)
{
context.Result = new JsonResult
{
Data = ((ViewResult)context.Result).ViewData.Model
};
}
}
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