在填字游戏中找到一个单词

问题描述

编写一个名为capitalize_word_in_crossword的函数，该函数接受二维字符列表(如填字游戏)和字符串(单词)作为输入参数.此功能搜索2d列表的行和列，以查找单词的匹配项.如果找到匹配项，则此函数将二维列表中的匹配字符大写并返回列表.如果找不到匹配项，则此函数将直接返回原始的二维列表，而无需进行任何修改.

Write a function named capitalize_word_in_crossword that accepts a 2-dimensional list of characters (like a crossword puzzle) and a string (word) as input arguments. This function searches the rows and columns of the 2d list to find a match for the word. If a match is found, this functions capitalizes the matched characters in 2-dimensional list and returns the list. If no match is found, this function simply returns the original 2-dimensional list with no modification.

示例1:如果如下所示调用函数:

Example 1: If the function is called as shown below:

文字:

crosswords=[['s','d','o','g'],['c','u','c','m'],['a','x','a','t'],['t','e','t','k']]
word='cat'
capitalize_word_in_crossword(crosswords,word)

然后您的函数应返回:

请注意，上面的列表代表了二维填字游戏，如下所示.

Notice that the above list is a representation for a 2-dimensional crossword puzzle as shown below.

示例2:如果如下所示调用函数:

Example 2: if the function is called as shown below:

文字:

crosswords=[['s','d','o','g'],['c','u','c','m'],['a','c','a','t'],['t','e','t','k']]
word='cat'
capitalize_word_in_crossword(crosswords,word)

然后您的函数应返回:

请注意，上面的列表代表了二维填字游戏，如下所示.

Notice that the above list is a representation for a 2-dimensional crossword puzzle as shown below.

注意:如果同时找到水平和垂直匹配，则仅选择水平匹配.例如，在上述情况下，水平匹配从[2,1]开始，垂直匹配也从[1,0]开始.请注意，在返回的列表中，只有水平匹配的字符才能大写.

Note: If both a horizontal and a vertical match is found then only select the horizontal match. For example, in the above case there is a horizontal match starting at [2,1] and there is also a vertical match starting at [1,0]. Notice that only the characters in the horizontal match should be capitalized in the returned list.

我尝试过此代码，该代码只能找到水平单词.

I have tried this code which only finds the horizontal words.

def find_word_horizontal(crosswords,word):
    list1=[]
    row_index = -1
    column_index = -1
    refind=''
    for row in crosswords:
        index=''
        for column in row:
            index= index+column
        list1.append(index)

    for find_word in list1:
        if word in find_word:
           row_index = list1.index(find_word)
           refind = find_word
           column_index = find_word.index(word)

    ret = [row_index,column_index]
    if row_index!= -1 and column_index != -1:
        return ret

不知道该怎么做.请帮忙.

Don't know what to do further. Please help.

推荐答案

现在是正确的.

我有缩进问题和水平/垂直分割索引

i had indentation problem and split index for horizontal/vertical

def capitalize_word_in_crossword(crosswords,word):
     i_v=-1
     j_v=-1
     i_h=-1
     j_h=-1
     index_cap = find_word_horizontal(crosswords,word)
     if index_cap is not None:
        i_h,j_h=index_cap
     else:
        index_cap = find_word_vertical(crosswords,word)
        if index_cap is not None:
           i_v,j_v=index_cap


     for row_index in range(len(crosswords)):
         for col_index in range(len(crosswords[row_index])):

             for w in range(len(word)):
                 if i_h is not -1:
                    if row_index==i_h and col_index==j_h+w:
                       crosswords[row_index][col_index] = (crosswords[row_index][col_index]).upper()

                 if i_v is not -1:
                    if row_index==i_v+w and col_index==j_v:
                       crosswords[row_index][col_index] = (crosswords[row_index][col_index]).upper()
                    else:
                       crosswords[row_index][col_index] = (crosswords[row_index][col_index])

     return (crosswords)

这篇关于在填字游戏中找到一个单词的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！