本文介绍了显示表单时如何运行代码?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我认为 Load 事件可能会有所帮助,但以下代码只是立即显示完成".
I thought the Load event might help, but the following code just shows "Done" immediately.
public Form1()
{
InitializeComponent();
Load += new EventHandler(Form1_Load);
}
void Form1_Load(object sender, EventArgs e)
{
System.Threading.Thread.Sleep(3000);
Text = "Done";
}
如何在表单显示后让它休眠?
How do I make it Sleep after the form is shown?
谢谢.
推荐答案
Windows 窗体有一个 Shown 事件.查看:http://msdn.microsoft.com/en-us/library/system.windows.forms.form.shown.aspx
There is a Shown event for a windows form. Check out: http://msdn.microsoft.com/en-us/library/system.windows.forms.form.shown.aspx
或者,如果你很懒惰,那就来吧:
Or if you are lazy, here you go:
public Form1()
{
InitializeComponent();
Shown += Form1_Shown;
}
private void Form1_Shown(object sender, EventArgs e)
{
System.Threading.Thread.Sleep(3000);
Text = "Done";
}
享受.
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