提升：包含指针类实例的序列化

问题描述

如果我序列化类的一个实例的集装箱，使用Boost库：

If I serialize an instance of the class Container, using Boost library:

class Container
{
   public:
      Block** blocks;
      int blocksNumber;
}

class Block
{
   public:
     int blockType;
     unsigned char* data;
}

然后填写所有必要的数据，以得到一个完整的容器：

And then filling all the necessary data to get a complete Container:

Container container = new Container();
container.blocksNumber=5;
Block** blocks = (Block**)malloc(sizeof(Block*)*container.blocksNumber);
blocks[0] = (Block*)malloc(sizeof(Block));
//..... Filling all the necessary data... and constructing the container

所以我的问题是：实例的​​序列化格式的容器包含所有分配的数据？换句话说，如果我反序列化容器的序列化格式，将我能够阅读的数据内容？谢谢了很多！

So my question is: Would the serialized format of the instance container contain all the allocated data? In other words, if I deserialize the serialized format of container, would I be able to read the content of data? Thank you a lot!

推荐答案

我不打算为什么你这里带来不安全Ç大炮浪费任何时间考虑。你打算使用升压序列化，现代化通用的C ++库。

I'm not going to waste any time contemplating why you bring unsafe C cannons in here. You're looking to use Boost Serialization, a modern generic C++ library.

下面是它应该是什么样子：

Here's what it should look like:

struct Block {
    int blockType;
    std::vector<uint8_t> data;
};

struct Container {
    std::vector<std::vector<Block>> block_lists;
};

看到一个完整的工作示例：

See a complete working sample:

#include <boost/serialization/vector.hpp>

class Block
{
   public:
     int blockType;
     std::vector<uint8_t> data;

   private:
       friend class boost::serialization::access;
       template <typename Ar> void serialize(Ar& ar, unsigned) {
               ar & blockType;
               ar & data;
           }
};

class Container
{
   public:
       std::vector<std::vector<Block>> block_lists;

   private:
       friend class boost::serialization::access;
       template <typename Ar> void serialize(Ar& ar, unsigned) {
               ar & block_lists;
           }
};

#include <boost/archive/text_oarchive.hpp>

int main()
{
    Container const letshavesome = {
        { // block_lists
            {
                Block { 1, { 0x11, 0x12, 0x13, 0x14 } },
                Block { 2, { 0x21, 0x22, 0x23, 0x24 } },
                Block { 3, { 0x31, 0x32, 0x33, 0x34 } },
            },
            {
                Block { 4, { 0x41, 0x42, 0x43, 0x44 } },
                Block { 5, { 0x51, 0x52, 0x53, 0x54 } },
                Block { 6, { 0x61, 0x62, 0x63, 0x64 } },
            },
        }
    };

    boost::archive::text_oarchive oa(std::cout);
    oa << letshavesome;
}

输出

22 ::系列化存档11 0 0 0 0 2 0 0 0 3 0 0 0 1 0 4 17 18 19 20 2 4 0 33 34 35 36 3 4 0 49 50 51 52 3 0 4 4 0 65 66 67 68 5 4 0 81 82 83 84 6 4 0 97 98 99 100

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