问题描述
我已经在stackoverflow上搜索了答案,但是找不到相关的东西.
I've searched stackoverflow for an answer but I cannot get something relevant.
我试图通过指定初始值来初始化具有初始值的静态结构实例,但是在编译时出现错误:
I'm trying to initialize a static structure instance with initial values by specifying their tags, but I get an error at compilation time:
src/version.cpp:10: error: expected primary-expression before ‘.’ token
代码如下:
// h
typedef struct
{
int lots_of_ints;
/* ... lots of other members */
const char *build_date;
const char *build_version;
} infos;
错误代码:
// C
static const char *version_date = VERSION_DATE;
static const char *version_rev = VERSION_REVISION;
static const infos s_infos =
{
.build_date = version_date, // why is this wrong? it works in C!
.build_version = version_rev
};
const infos *get_info()
{
return &s_infos;
}
因此,基本思想是绕过其他成员"初始化,而仅设置相关的build_date
和build_version
值.这曾经可以在C语言中使用,但我不知道为什么它不能在C ++中使用.
So the basic idea is to bypass the "other members" initialization and only set the relevant build_date
and build_version
values.This used to work in C, but I can't figure out why it won't work in C++.
有什么想法吗?
修改:
我意识到这段代码看起来像简单的C,实际上是这样.整个项目都是C ++,因此我必须使用C ++文件扩展名来防止makefile依赖关系混乱(%.o: %.cpp
)
I realize this code looks like simple C, and it actually is. The whole project is in C++ so I have to use C++ file extensions to prevent the makefile dependency mess ( %.o: %.cpp
)
推荐答案
您正在使用的功能是C99功能,并且您正在使用不支持该功能的C ++编译器.请记住,尽管C代码通常是有效的C ++代码,但C99代码并非总是如此.
The feature you are using is a C99 feature and you are using a C++ compiler that doesn't support it. Remember that although C code is generally valid C++ code, C99 code isn't always.
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