问题描述
我有这样的情况
public class Test{
static int a;
int b;
public static void main(String[] args){
Test t1 = new Test();
Test t2 = new Test();
}
}
对象t1和对象t2中的变量是什么?
What will be the variables in object t1 and object t2?
根据我的理解，由于变量 a 是静态变量，因此它将同时存在于对象1和对象2中.
As per my understanding since variable a is a static variable it will be both in object 1 and object 2.
和 b 将为两个对象创建单独的副本.
And b will be created separate copy for both the objects.
但是当我给变量b即( int b = 1 )赋值并像 System.out.println(t1.b)那样调用它时， System.out.println(t2.b)
But when I assign a value to variable b ie(int b=1) and call it like System.out.println(t1.b), System.out.println(t2.b)
这两个对象的输出不是1，而是错误.
Instead of getting an error I am getting 1 as output from both the objects.
那是为什么?
推荐答案
不.它都不在 对象中.它的存在根本不涉及任何特定实例.尽管Java 允许，您还是可以通过引用来引用它，例如 int x = t1.a; 不应这样做.相反，您应该通过类名称(在您的情况下为 test.a 来引用它-尽管您还应该开始遵循Java命名约定)以使其清晰可见.
No. It's not in either object. It exists without reference to any particular instance at all. Although Java allows you to refer to it "via" a reference, e.g. int x = t1.a; you shouldn't do so. You should instead refer to it via the class name (test.a in your case - although you should also start following Java naming conventions) to make it clear that it's static.
是的
那是因为您已经为它赋予了一个初始值，可以为每个新对象分配初始值.那是完全合理的.仍然有两个自变量:
Well that's because you've basically given it an initial value to assign for each new object. That's entirely reasonable. There are still two independent variables:
t1.b = 2;
t2.b = 3;
System.out.println(t1.b); // Prints 2
System.out.println(t2.b); // Prints 3
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