将字符串长度缩短1

本文介绍了将字符串长度缩短1的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！

问题描述

我想通过用''\0''替换最后一个字符来缩短字符串。

以下代码显示字符串。它工作正常。这是在一个

循环中，不同的字符串显示没有问题。

------------------- ----------------------------------------

temp = strlen（aGroup）;

for（i = 0; i< temp; i ++）

printf（"％d％d％c\ n，i + 1，temp，aGroup [i]）;

-------------------------------- -------------------------

用''\ 0'替换最后一个字符，我已经尝试了

aGroup [i-1] =''\ 0'';

或

temp--;

aGroup [temp] =''\ 0'';

或

aGroup [ temp-1] =''\''';

虽然没有编译错误，程序在运行时崩溃了

（我被问到是否向Microsoft发送错误报告。同样的错误

这三个。）

但是aGroup [22] =''\'''; "工作（我知道长度大于22）。

给出了什么？这是在VC ++ 6.0上。

解决方案

验证aGroup是否已正确声明，并且它是足够大到足以存储字符串的b $ b正在复制它。

也许你正在溢出一个缓冲区，或忘了正确调用

malloc？

-Jason

-Jason

验证aGroup是否已正确声明，并且它足够大，足以存储您要复制到其中的字符串。
也许你是在满溢缓冲区，或忘了正确调用了malloc？

-Jason
-Jason

感谢您的回复。

正如我所说。该程序工作正常，直到我添加代码（三个中的任何一个

）来替换最后一个字符。我认为这应该排除你提到的潜在问题。

BTW，aGroup被声明为char aGroup [2048];这可能比它的价格大10倍。

你能发贴实际的代码吗？没有进一步的信息我很害怕

我无法帮助你。

-Jason

I want to shorten a string by replacing the last character by ''\0''.

The following code displays the string. It works fine. It''s in a
loop and different strings are displayed without problems.
-----------------------------------------------------------
temp= strlen(aGroup);
for (i=0; i< temp;i++)
printf(" %d %d %c\n", i+1,temp,aGroup[i]);
---------------------------------------------------------

To replace the last character by ''\0'', I have tried

aGroup[i-1]=''\0'';

or
temp--;
aGroup[temp]=''\0'';

or
aGroup[temp-1]=''\0'';

Though there is no compiling error, the program crashed when ran
(I was asked whether to send error report to Microsoft. Same error
for all three.)

But "aGroup[22]=''\0'';" works (I knew the length is greater than 22.)

What gives? This is on VC++ 6.0.

解决方案

Verify that aGroup has been properly declared, and that it is
suffiently large enough to store the string you are copying into it.
Perhaps you are overflowing a buffer, or forgot to properly call
malloc?

-Jason
-Jason

Thanks for the reply.

As I said. The program worked fine until I added the code (any one
of the three) to replace the last character. I think this should
rule out the potential problems you mentioned.

BTW, aGroup is declared as "char aGroup[2048];" which is probably
10 times larger than what it can be.

Could you post the actual code? Without further information I''m afraid
I won''t be able to assist you.

-Jason

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