问题描述
由于某些原因,我不知道为什么数据打开时不会被放入数组和程序崩溃。我已经搜索了一个答案没有效果。我得到的感觉,我会在这里发布几次,在我完成这个程序之前!
For some reason or another I cannot figure out why the data when opened does not get put into arrays and the program crashes. I have searched around for a answer to no avail. I get the feeling I will be posting a here a few more times before I finish this program!
#include <iostream>
#include <string>
#include <fstream>
using namespace std;
string bookTitle [14];
string bookAuthor [14];
int loadData (string pathname);
void showall (int counter);
int main ()
{
int counter;
string pathname;
cout<<"Input the name of the file to be accessed: ";
cin>>pathname;
loadData (pathname);
showall (counter);
cout<<"Press <Enter> to Exit";
cin.ignore();
cin.get();
return 0;
}
int loadData (string pathname) // Loads data from infile into arrays
{
fstream infile;
int counter = 0;
infile.open(pathname.c_str()); //Opens file from user input in main
if( infile.fail() )
{
cout << "File failed to open";
return 0;
}
while (!infile.eof())
{
cout<<"File Opened"; // I get the "File Opened" text and then a crash
infile >> bookTitle [14] ; //takes input and puts into parallel arrays
infile >> bookAuthor [14];
cout<<"Data Put in Arrays";
counter++;
}
infile.close();
}
void showall (int counter) // shows input in title(author) format
{
cout<<bookTitle<<"("<<bookAuthor<<")";
}
编辑:分配是取一个文件名,格式如title
author
title
author
然后它必须以标题(作者)格式输出数组到屏幕。
The assignment is to take a file with names in a format such as title author title authorThen it must output the arrays to screen in a title(author) format.
之后,我必须使它成为一个循环程序,所以可以从一个数组中选择一个搜索,并以标题(作者)格式返回条目。
After this I must make it a looping program so a search can be chosen of one of the arrays and returns the entry in a title(author) format.
代码现在如何;
#include <iostream>
#include <string>
#include <fstream>
using namespace std;
string bookTitle [50];
string bookAuthor [50];
int loadData (string pathname);
int showall (int counter);
int main ()
{
string pathname;
int counter=0;
cout<<"Input the name of the file to be accessed: ";
cin>>pathname;
loadData (pathname);
showall (counter);
cout<<"Press <Enter> to Exit";
cin.ignore();
cin.get();
return 0;
}
int loadData (string pathname) // Loads data from infile into arrays
{
fstream infile;
int counter = 0;
infile.open(pathname.c_str()); //Opens file from user input in main
if( infile.fail() )
{
cout << "File failed to open";
return 0;
}
while (!infile.eof())
{
infile >> bookTitle [counter] ; //takes input and puts into parallel arrays
infile >> bookAuthor [counter];
counter++;
}
infile.close();
}
int showall (int counter) // shows input in title(author) format
{
cout<<bookTitle<<"("<<bookAuthor<<")";
return 0;
}
推荐答案
:
infile >> bookTitle [14] ;
infile >> bookAuthor [14];
不正确,您需要的是:
infile >> bookTitle[counter];
infile >> bookAuthor [counter];
此外,
在 main()
和 loadData()
中声明的$ c> counter 不同的变量。在 main()
中声明的一个不会被初始化。
The counter
variable declared in main()
and in loadData()
are two different variables. The one declared in main()
is never iniitalized at all.
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