本文介绍了System.Text.JSON不会反序列化Newtonsoft的功能的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我有一个json,新的System.Text.Json.JsonSerializer.Deserialize<T>(json_data)用正确数量的元素序列化为List<T>,但是里面的对象的所有值都为null或0

I have a json that the new System.Text.Json.JsonSerializer.Deserialize<T>(json_data) serialize as List<T> with the correct numbers of elements, but then the objects inside have all the values null or 0

Newtonsoft.Json.JsonConvert.DeserializeObject<T>(json_data)相同的json已正确填充.

Same json with Newtonsoft.Json.JsonConvert.DeserializeObject<T>(json_data) is correctly filled.

班级:

public class SensorValue
    {
        public string StationCode { get; set; }
        public string SensorCode { get; set; }
        public string SensorNameIt { get; set; }
        public string SensorNameDe { get; set; }
        public string SensorNameLd { get; set; }
        public string SensorUnitMeasure { get; set; }
        public DateTime SamplingDateTime { get; set; }
        public Decimal SamplingValue { get; set; }
    }

JSON

[{"stationCode":"89190MS","sensorCode":"LT","sensorNameIt":"Temperatura dell´aria","sensorNameDe":"Lufttemperatur","sensorNameLd":"Temperatura dl’aria","sensorUnitMeasure":"°C","samplingDateTime":"2019-11-15T15:10:00","samplingValue":0.3},{"stationCode":"89190MS","sensorCode":"N","sensorNameIt":"Precipitazioni","sensorNameDe":"Niederschlag","sensorNameLd":"plueia","sensorUnitMeasure":"mm","samplingDateTime":"2019-11-15T15:10:00","samplingValue":0.4},{"stationCode":"89190MS","sensorCode":"WR","sensorNameIt":"Direzione del vento","sensorNameDe":"Windrichtung","sensorNameLd":"Direzion dl vënt","sensorUnitMeasure":"° ","samplingDateTime":"2019-11-15T15:10:00","samplingValue":165.7},{"stationCode":"89190MS","sensorCode":"WG","sensorNameIt":"Velocità del vento","sensorNameDe":"Windgeschwindigkeit","sensorNameLd":"Slune dl vënt","sensorUnitMeasure":"m/s","samplingDateTime":"2019-11-15T15:10:00","samplingValue":0.7},{"stationCode":"89190MS","sensorCode":"WG.BOE","sensorNameIt":"Velocitá raffica","sensorNameDe":"Windgeschwindigkeit Böe","sensorNameLd":"Slune dl vënt","sensorUnitMeasure":"m/s","samplingDateTime":"2019-11-15T15:10:00","samplingValue":1.3},{"stationCode":"89190MS","sensorCode":"LF","sensorNameIt":"Umidità relativa","sensorNameDe":"relative Luftfeuchte","sensorNameLd":"Tume relatif","sensorUnitMeasure":"%","samplingDateTime":"2019-11-15T15:10:00","samplingValue":100.0},{"stationCode":"89190MS","sensorCode":"LD.RED","sensorNameIt":"Pressione atmosferica","sensorNameDe":"Luftdruck","sensorNameLd":"Druch dl’aria","sensorUnitMeasure":"hPa","samplingDateTime":"2019-11-15T15:10:00","samplingValue":1006.9},{"stationCode":"89190MS","sensorCode":"GS","sensorNameIt":"Radiazione globale ","sensorNameDe":"Globalstrahlung","sensorNameLd":"Nraiazion globala ","sensorUnitMeasure":"W/m²","samplingDateTime":"2019-11-15T15:10:00","samplingValue":3.8},{"stationCode":"89190MS","sensorCode":"SD","sensorNameIt":"Durata soleggiamento","sensorNameDe":"Sonnenscheindauer","sensorNameLd":"Dureda dl surëdl","sensorUnitMeasure":"s","samplingDateTime":"2019-11-15T15:10:00","samplingValue":0.0}]

有什么帮助吗?consoleapp项目.net core 3.0.0牛顿软件12.0.3

Any help ?consoleapp project .net core 3.0.0newtonsoft 12.0.3

推荐答案

System.Text.Json解串器的默认行为是将属性匹配为区分大小写.您需要传递告诉它与大小写无关的选项:

The default behavior of the System.Text.Json deserializer is to match properties as case sensitive. You need to pass options telling it to match case insensitive:

using System.Text.Json;

JsonSerializer.Deserialize<T>(json_data, new JsonSerializerOptions
{
    PropertyNameCaseInsensitive = true
});

这篇关于System.Text.JSON不会反序列化Newtonsoft的功能的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!

09-02 10:17