问题描述
我想根据条件更改detailview中单个属性的类:
I would like to change class for one single attribute in detailview, based on a condition:
如果我不想让它成为有条件的,它将是像这样工作:
If I wouldn't want to make it conditional, it would be working like so:
[
'attribute' => 'ungueltig',
'format' => 'boolean',
'contentOptions' => [
'class' => 'danger',
]
],
我希望这个改变有条件的,我已经尝试了很多不同的方式,例如:
I want this one to change to conditional, and I have tried a lot of different ways, e.g.:
[
'attribute' => 'ungueltig',
'format' => 'boolean',
'contentOptions' => function ($model) {
if ($model->ungueltig == 1) {
return ['class' => 'danger'];
} else {
return '';
}
},
],
(我想这是最合乎逻辑的解决方案,但没有任何反应,因此页面加载正常但属性没有类危险,没有错误消息)
(I would think this is the most logical solution, but nothing happens, so page is loading fine but without class danger at the attribute, no error message)
或
[
'attribute' => 'ungueltig',
'format' => 'boolean',
'contentOptions' => ['class' => function ($model) {
if ($model->ungueltig == 1) {
return 'danger';
} else {
return '';
}
},]
],
=错误讯息: htmlspecialchars()期望参数1为字符串,给定对象
所以我没有任何线索,我甚至找不到任何帮助网络。你能指点我正确的方向吗?非常感谢!
so I have no clue and I don't even find any help on the web. Can you please point me to the right direction? Many thanks!
推荐答案
您应该尝试:
'contentOptions' => [
'class' => ($model->ungueltig == 1) ? 'danger' : '',
],
DetailView
只显示一个模型,这里不需要任何函数。
DetailView
display only one model, you don't need any function here.
这篇关于yii2 detailview条件行类的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!