合并 BG 为 JPEG 的图像会导致意外结果

问题描述

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为什么合并 BG 为 JPEG 的图像会导致意外结果?

这是我在 中，形成的代码组合图像是

Graphics2D g = finalImage.createGraphics();g.drawImage(bgImage, 0, 0, null);g.drawImage(fgImage, 0, 0, null);

但是在这个问题中，它已更改为，

Graphics2D g = finalImage.createGraphics();g.drawImage(bgImageJpeg, w, h, null);g.drawImage(fgImage, w, h, null);

后者开始在 "左上角"，恰好是图片的右下角，所以什么都不是画.然而，前者按预期绘制了整个图像.

Why does combining images where BG is a JPEG cause unexpected results?

This is a follow-up to my answer in Overlaying of 2 images doesnt work properly. The source posted there (using a BG image created in memory) looks like this:

• The BG image is on the left.
• The FG image (a PNG with transparency) is in the middle.
• The combined image is on the right.

So far, so good. But then the person who asked the question commented that if the BG was a JPEG, it failed. Thinking they were mistaken, I altered my example to encode the BG image to a JPEG. Now if I use BufferedImage.TYPE_INT_ARGB or BufferedImage.TYPE_INT_RGB for the final image I get what they were referring to:

TYPE_INT_ARGB

TYPE_INT_RGB

I expected the result to be the same as the original for at least one of those (more so the ARGB variant).

import java.awt.*;
import java.awt.image.BufferedImage;
import javax.swing.*;
import java.io.ByteArrayInputStream;
import java.io.ByteArrayOutputStream;
import java.net.URL;
import javax.imageio.ImageIO;

class CombineImages {

    public static void main(String[] args) {
        Runnable r = new Runnable() {

            @Override
            public void run() {
                try {
                    URL urlImage1 =
                        new URL("http://i.stack.imgur.com/T5uTa.png");

                    // Load the FG image
                    Image fgImage = ImageIO.read(urlImage1);
                    int w = fgImage.getWidth(null);
                    int h = fgImage.getHeight(null);
                    // Create a non-trasparent BG image
                    BufferedImage bgImageTemp =
                            new BufferedImage(w,h,BufferedImage.TYPE_INT_RGB);

                    ByteArrayOutputStream baos =
                        new ByteArrayOutputStream();
                    ImageIO.write(bgImageTemp, "jpg", baos);
                    ByteArrayInputStream bais =
                        new ByteArrayInputStream(baos.toByteArray());
                    BufferedImage bgImageJpeg = ImageIO.read(bais);

                    int result = JOptionPane.showConfirmDialog(
                        null,
                        "Use a final image with transparency?",
                        "Transparency",
                        JOptionPane.YES_NO_OPTION);

                    int type = (result==JOptionPane.OK_OPTION ?
                        BufferedImage.TYPE_INT_ARGB :
                        BufferedImage.TYPE_INT_RGB);

                    // Create the final image
                    BufferedImage finalImage =
                            new BufferedImage(w,h,type);
                    Graphics2D g = finalImage.createGraphics();
                    g.drawImage(bgImageJpeg, w, h, null);
                    g.drawImage(fgImage, w, h, null);
                    g.dispose();

                    JPanel gui = new JPanel(new GridLayout(1,0,5,5));

                    gui.add(new JLabel(new ImageIcon(bgImageJpeg)));
                    gui.add(new JLabel(new ImageIcon(fgImage)));
                    gui.add(new JLabel(new ImageIcon(finalImage)));

                    JOptionPane.showMessageDialog(null, gui);
                } catch (Exception e) {
                    e.printStackTrace();
                }
            }
        };
        SwingUtilities.invokeLater(r);
    }
}

解决方案

Looks like this is due to a typo.

In your referenced answer, the code that formed the combined image was

Graphics2D g = finalImage.createGraphics();
g.drawImage(bgImage, 0, 0, null);
g.drawImage(fgImage, 0, 0, null);

But in this question, it's been changed to,

Graphics2D g = finalImage.createGraphics();
g.drawImage(bgImageJpeg, w, h, null);
g.drawImage(fgImage, w, h, null);

The latter begins drawing at the "top-left corner", which happens to be the bottom-right corner of the images, so nothing is really drawn. The former, however, draws the entire images, as expected.

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