本文介绍了实例上的Groovy Mixin(Dynamic Mixin)的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
class A {
def foo(){foo }
}
class B {
def bar(){bar}
}
A.mixin B
def a = new A()
a.foo()+ a.bar()
有一个显着差异 - 我想在实例上进行mixin:
a.mixin B
但这会导致
groovy.lang.MissingMethodException:没有方法的签名:A.mixin()适用于参数类型:(java.lang.Class)values:[class B]
有没有办法让这个工作像在?
解决方案
您可以从Groovy 1.6
在实例metaClass上调用mixin如下:
class A {
def foo() {foo}
}
class B {
def bar(){bar}
}
def a =新的A()
a.metaClass.mixin B
a.foo()+ a.bar()
I'm trying to achieve following:
class A {
def foo() { "foo" }
}
class B {
def bar() { "bar" }
}
A.mixin B
def a = new A()
a.foo() + a.bar()
with one significant difference - I would like to do the mixin on the instance:
a.mixin B
but this results in
groovy.lang.MissingMethodException: No signature of method: A.mixin() is applicable for argument types: (java.lang.Class) values: [class B]
Is there a way to get this working like proposed in the Groovy Mixins JSR?
解决方案
You can do this since Groovy 1.6
Call mixin on the instance metaClass like so:
class A {
def foo() { "foo" }
}
class B {
def bar() { "bar" }
}
def a = new A()
a.metaClass.mixin B
a.foo() + a.bar()
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