sklearn估计器管道的参数无效

问题描述

我正在使用Python 2.7和sklearn 0.16实现O'Reilly的书" Python机器学习入门"中的示例.

I am implementing an example from the O'Reilly book "Introduction to Machine Learning with Python", using Python 2.7 and sklearn 0.16.

我正在使用的代码:

pipe = make_pipeline(TfidfVectorizer(), LogisticRegression())
param_grid = {"logisticregression_C": [0.001, 0.01, 0.1, 1, 10, 100], "tfidfvectorizer_ngram_range": [(1,1), (1,2), (1,3)]}
grid = GridSearchCV(pipe, param_grid, cv=5)
grid.fit(X_train, y_train)
print("Best cross-validation score: {:.2f}".format(grid.best_score_))

返回的错误归结为:

ValueError: Invalid parameter logisticregression_C for estimator Pipeline

这是与使用v.0.16版中的Make_pipeline有关的错误吗?是什么导致此错误?

Is this an error related to using Make_pipeline from v.0.16? What is causing this error?

推荐答案

在管道logisticregression__C.对tfidfvectorizer

请参见 http://scikit-learn.org/stable/auto_examples/plot_compare_reduction.html#sphx-glr-auto-examples-plot-compare-reduction-py

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