是否可以通过 git 别名覆盖 git 命令?

问题描述

我的 ~/.gitconfig 是:

my ~/.gitconfig is:

[alias]
        commit = "!sh commit.sh"

但是，当我输入 git commit 时，不会调用脚本.

However, when I type git commit, script is not called.

是否可以，或者我必须使用其他别名?

Is it possible, or I have to use another alias name?

推荐答案

这不可能

这是来自我的 git.git 克隆:

This is from my clone of git.git:

static int run_argv(int *argcp, const char ***argv)
{
    int done_alias = 0;

    while (1) {
        /* See if it's an internal command */
        handle_internal_command(*argcp, *argv);

        /* .. then try the external ones */
        execv_dashed_external(*argv);

        /* It could be an alias -- this works around the insanity
         * of overriding "git log" with "git show" by having
         * alias.log = show
         */
        if (done_alias || !handle_alias(argcp, argv))
            break;
        done_alias = 1;
    }

    return done_alias;
}

所以这是不可能的.(handle_internal_command 如果找到命令则调用 exit).

So its not possible. (handle_internal_command calls exit if it finds the command).

您可以通过更改行的顺序并让 handle_alias 调用 exit(如果找到别名)来解决此问题.

You could fix this in your sources by changing the order of the lines and making handle_alias call exit if it finds the alias.

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