问题描述
如何调用第一个函数的返回值到第二个函数?这是第一个计算客户对我店的访问次数的函数:
How can I call the return value of the first function into the second function? Here is the first function to count the number of visits a customer makes to my shop:
CREATE OR REPLACE FUNCTION CALCULATE ( NUM CUSTOMER.CUST_VISIT%TYPE)
RETURN NUMBER
IS
V_CUST_VISIT NUMBER(3);
V_COUNT INTEGER;
BEGIN
SELECT CUST_VISIT
INTO V_CUST_VISIT
FROM CUSTOMER, BOOKING
WHERE CUSTOMER.CUST_ID = BOOKING.CUST_ID;
SELECT MAX(COUNT(*))
INTO v_count
FROM BOOKING
GROUP BY CUST_ID
HAVING count(*)>=0;
CASE v_count
WHEN 3 THEN v_cust_visit:= v_count;
DBMS_OUTPUT.PUT_LINE('10% DISCOUNT DUE');
WHEN 6 THEN v_cust_visit:= v_count;
DBMS_OUTPUT.PUT_LINE('20% DISCOUNT DUE');
WHEN 9 THEN v_cust_visit:= v_count;
DBMS_OUTPUT.PUT_LINE('30% DISCOUNT DUE');
ELSE v_cust_visit:= v_count;
DBMS_OUTPUT.PUT_LINE('OOPS NO DISCOUNT DUE YET! AFTER THREE BOOKINGS');
END CASE;
END;
/
Where in the second function:
CREATE OR REPLACE FUNCTION CALC_BILL
(BILL_NUM TREATMENT.TREAT_COST%TYPE)
RETURN NUMBER
IS
CUST_ID VARCHAR2(4);
TREAT_COST NUMBER(10,2);
v_TREAT_cost TREATMENT.TREAT_COST%TYPE;
DISCOUNTED_BILL NUMBER(10,2);
NO_DISCOUNT EXCEPTION;
BEGIN
SELECT TREAT_COST
INTO v_treat_cost
FROM CUSTOMER C, TREATMENT T, TREAT_SESSION TS
WHERE C.CUST_ID = TS.CUST_ID
AND T.TREAT_ID = TS.TREAT_ID;
IF
CALCULATE():= 3 - 这是我如何尝试, work--
THEN
DISCOUNTED_BILL:= v_treat_cost-(v_treat_cost * 0.1);
IF CALCULATE() :=3 --this is how I tried and it hasnt work-- THEN DISCOUNTED_BILL:= v_treat_cost-(v_treat_cost*0.1);
ELSIF
CALCULATE:= 6
THEN
DISCOUNTED_BILL:= v_treat_cost-(v_treat_cost * 0.2);
ELSIF CALCULATE := 6 THEN DISCOUNTED_BILL := v_treat_cost-(v_treat_cost*0.2);
ELSIF
CALCULATE:= 9
THEN
DISCOUNTED_BILL:= v_treat_cost-(v_treat_cost * 0.3);
ELSE
RAISE NO_DISCOUNT;
ELSIF CALCULATE := 9 THEN DISCOUNTED_BILL := v_treat_cost-(v_treat_cost*0.3); ELSE RAISE NO_DISCOUNT;
END IF;
END;
/
推荐答案
变量:
some_number_result := calculate(some_input);
if some_number_result = 1 then
-- do stuff
end if;
等...
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