本文介绍了学习SQL ...是否有更好的方法编写此代码?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
这是我要回答的问题...
This is the question I'm trying to answer...
在$ b中出现只有一名球员的所有球队的队名是什么$ b 145个或更多游戏?
What are the team names of all teams who had one and only one player appear in145 or more games?
这是我的解决方案。
SELECT name
From Teams
WHERE teamID IN (SELECT original.teamID
FROM Appearances original
WHERE teamID Not In (SELECT one.teamID
FROM Appearances one, Appearances two
Where (one.teamID = two.teamID)
AND (one.playerID <> two.playerID)
AND (one.GS > 144) AND (two.GS > 144)));
这行得通,但我想知道是否有更干净/更有效的方式编写此代码。我正在使用Derby作为我的dbms。
This works, but I'm wondering if there is a cleaner/more efficient way to write this. I'm using Derby as my dbms.
推荐答案
我不确定您的查询是否有效。我希望它更像这样:
I'm not sure if your query does work. I would would expect it to be more like this:
SELECT name
FROM Teams
WHERE teamID IN
( SELECT one.teamID
FROM Appearances one
WHERE (one.GS > 144)
AND one.teamID NOT IN
( SELECT two.teamID
FROM Appearances two
WHERE (one.teamID = two.teamID)
AND (one.playerID <> two.playerID)
AND (two.GS > 144) ) );
这篇关于学习SQL ...是否有更好的方法编写此代码?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!