问题描述
我正在用C ++编写一个用于链表的程序.为了实现这一概念，我在全局创建了一个指针"start"，指向列表的第一个元素.
I was making a program for linked list in C++. To implement the concept, I created a pointer 'start' globally, pointing to the first element of the list.
程序完成后，我尝试通过使用start和另一个本地声明的指针"p"访问连续的节点，来删除动态分配的所有内存，以防止内存泄漏.在这里，我使用了一个指向相同正确地址的指针，但是该指针不是用于内存分配的指针，而是像任何普通指针一样在本地声明.
After completion of the program I tried to delete all memory allocated dynamically to prevent memory leaks, by accessing successive nodes using the start and another locally declared pointer 'p'.Here, I used a pointer pointing to the same correct addresses, but this pointer was not the one used for memory allocation, but was declared locally like any normal pointer.
我的问题是-是否可以通过使用指向相同位置的普通指针来删除动态分配的内存?
My question is - Is it possible to delete the dynamically allocated memory by using the normal pointers pointing to the same location?
推荐答案
可以.这是有效的:
int* p = new int;
int* q = p;
delete q;
使用新[] 时的等效项:
int* p = new int[123];
int* q = p;
delete[] q;
用指针类型替换 int * .之后是否将指针设置为 nullptr 仍在讨论之中.
Substitute int* with your pointer type. Whether to set the pointers to nullptr afterwards is up for debate.
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