问题描述
我有一个用户表,例如:
pre codereate table table user $ b $ id serial key,
名称文本不为空,
超级用户布尔值非空默认false
);
以及包含作业的表格:
create table job(
id serial primary key,
description text
);
可以将作业分配给用户,但仅限于超级用户。其他用户不能分配任务。
所以我有一个表格,我可以看到哪个工作分配给了哪个用户:
create table user_has_job(
user_id整数引用user(id),
job_id整数引用作业(id),$ b $约束user_has_job_pk PRIMARY KEY(user_id,job_id)
);
但是我想创建一个检查约束, user_id
引用具有 user.superuser = True
的用户。
这可能吗?或者还有另一种解决方案?
这对于INSERTS是有效的:
创建或替换函数is_superuser(int)返回布尔值为$$
select exists(
从user中选择
where id = $ 1
和superuser = true
);
$$语言sql;
然后在user_has_job表中检查一下:
pre $ create table user_has_job(
user_id整数引用user(id),
job_id整数引用job(id),
约束user_has_job_pk PRIMARY KEY(user_id,job_id),
约束chk_is_superuser检查(is_superuser(user_id))
);
适用于插入:
postgres =#insert intouser(name,superuser)values('name1',false);
INSERT 0 1
postgres =#insert intouser(name,superuser)values('name2',true);
INSERT 0 1
postgres =#insert into job(description)values('test');
INSERT 0 1
postgres =#insert into user_has_job(user_id,job_id)values(1,1);
错误:关系user_has_job的新行违反检查约束chk_is_superuser
详细信息:失败的行包含(1,1)。
postgres =#insert into user_has_job(user_id,job_id)values(2,1);
INSERT 0 1
然而这是可能的:
postgres =#updateuserset superuser = false;
UPDATE 2
所以如果你允许更新用户,你需要在用户表,以防止用户有工作。
I have a table of users eg:
create table "user" (
id serial primary key,
name text not null,
superuser boolean not null default false
);
and a table with jobs:
create table job (
id serial primary key,
description text
);
the jobs can be assigned to users, but only for superusers. other users cannot have jobs assigned.
So I have a table whereby I see which job was assigned to which user:
create table user_has_job (
user_id integer references "user"(id),
job_id integer references job(id),
constraint user_has_job_pk PRIMARY KEY (user_id, job_id)
);
But I want to create a check constraint that the user_id
references a user that has user.superuser = True
.
Is that possible? Or is there another solution?
This would work for INSERTS:
create or replace function is_superuser(int) returns boolean as $$
select exists (
select 1
from "user"
where id = $1
and superuser = true
);
$$ language sql;
And then a check contraint on the user_has_job table:
create table user_has_job (
user_id integer references "user"(id),
job_id integer references job(id),
constraint user_has_job_pk PRIMARY KEY (user_id, job_id),
constraint chk_is_superuser check (is_superuser(user_id))
);
Works for inserts:
postgres=# insert into "user" (name,superuser) values ('name1',false);
INSERT 0 1
postgres=# insert into "user" (name,superuser) values ('name2',true);
INSERT 0 1
postgres=# insert into job (description) values ('test');
INSERT 0 1
postgres=# insert into user_has_job (user_id,job_id) values (1,1);
ERROR: new row for relation "user_has_job" violates check constraint "chk_is_superuser"
DETAIL: Failing row contains (1, 1).
postgres=# insert into user_has_job (user_id,job_id) values (2,1);
INSERT 0 1
However this is possible:
postgres=# update "user" set superuser=false;
UPDATE 2
So if you allow updating users you need to create an update trigger on the users table to prevent that if the user has jobs.
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