Golang相当于Python的列表理解

问题描述

我正在玩Go，但我很难用其他语言做很简单的事情。

我想重现类似的语法：

  array = [a for a anotherArray if（some condition）] 
  

在Go中执行该操作的优雅方法是什么？我真的很想简化我的代码，特别是在数组上使用函数时。例如：对于范围（n）中的i，

  min = min（abs（a [i]，b [j] 
 for j in range（i，n））
  

非常感谢

解决方案

有趣的是，，它有点你想要的：

请参阅

  //选择一个类型为[] T的类型和一个类型为func的函数（ T）布尔。 （如果
 //输入条件不满足，请选择panics。）它将返回一个新的
 //分配的片，其中只包含
 //满足函数的输入片元素。 b 
 
 
 $ b 
 apply_test.go＃L67-L70rel =nofollow noreferrer>在此测试： 
 $ b 
  func TestChoose（t * testing.T）{
a：= [] int {1,2,3,4,5,6,7,8,9} 
 expect：= [] int {2,4,6 ，8} 
结果：=选择（a，isEven）
  
 As 指出中，，section ：
 
I am playing with Go but I am having a very hard time doing things that are very simple in other languages.
I'd like to reproduce a similar syntax:
array = [a for a in anotherArray  if (some condition)]
What is an elegant way to do it in Go? I'd really like to simplify my code especially when using function on array. For example:
min = min(abs(a[i], b[j]) for i in range(n)
                          for j in range(i, n))
Many thanks
 解决方案 
Interestingly enough, Rob Pike just proposed (18 hours ago) the library filter which does a bit what you want:
See for instance Choose()
// Choose takes a slice of type []T and a function of type func(T) bool. (If
// the input conditions are not satisfied, Choose panics.) It returns a newly
// allocated slice containing only those elements of the input slice that
// satisfy the function.
Tested here:
func TestChoose(t *testing.T) {
    a := []int{1, 2, 3, 4, 5, 6, 7, 8, 9}
    expect := []int{2, 4, 6, 8}
    result := Choose(a, isEven)
As twotwotwo points out in the comments, the GoDoc for this library states:
This caveat is reflected in the document "Summary of Go Generics Discussions", section "Functional Code":
                        
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