本文介绍了通过xslt1中的xml元素对重复节点进行xsl分组的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！
问题描述
我有一个复杂的 xml 结构，看起来像:
I have a complex xml structure that looks like :
<Items>
<Item>
<ItemTexts>
<ItemText>
<ItemTextsType>type1</ItemTextsType>
<ItemTextsTypeDesc>description11</ItemTextsTypeDesc>
<ItemTextsLine>1</ItemTextsLine>
</ItemText>
<ItemText>
<ItemTextsType>type1</ItemTextsType>
<ItemTextsTypeDesc>description12</ItemTextsTypeDesc>
<ItemTextsLine>2</ItemTextsLine>
</ItemText>
<ItemText>
<ItemTextsType>type2</ItemTextsType>
<ItemTextsTypeDesc>description21</ItemTextsTypeDesc>
<ItemTextsLine>3</ItemTextsLine>
</ItemText>
<ItemText>
<ItemTextsType>type2</ItemTextsType>
<ItemTextsTypeDesc>description22</ItemTextsTypeDesc>
<ItemTextsLine>4</ItemTextsLine>
</ItemText>
</ItemTexts>
</Item>
<Item>
<ItemTexts>
<ItemText>
<ItemTextsType>type1</ItemTextsType>
<ItemTextsTypeDesc>description11</ItemTextsTypeDesc>
<ItemTextsLine>1</ItemTextsLine>
</ItemText>
<ItemText>
<ItemTextsType>type1</ItemTextsType>
<ItemTextsTypeDesc>description12</ItemTextsTypeDesc>
<ItemTextsLine>2</ItemTextsLine>
</ItemText>
<ItemText>
<ItemTextsType>type2</ItemTextsType>
<ItemTextsTypeDesc>description21</ItemTextsTypeDesc>
<ItemTextsLine>3</ItemTextsLine>
</ItemText>
<ItemText>
<ItemTextsType>type2</ItemTextsType>
<ItemTextsTypeDesc>description22</ItemTextsTypeDesc>
<ItemTextsLine>4</ItemTextsLine>
</ItemText>
</ItemTexts>
</Item>
<Item>
<ItemTexts>
<ItemText>
<ItemTextsType>type1</ItemTextsType>
<ItemTextsTypeDesc>description11</ItemTextsTypeDesc>
<ItemTextsLine>1</ItemTextsLine>
</ItemText>
<ItemText>
<ItemTextsType>type1</ItemTextsType>
<ItemTextsTypeDesc>description12</ItemTextsTypeDesc>
<ItemTextsLine>2</ItemTextsLine>
</ItemText>
<ItemText>
<ItemTextsType>type2</ItemTextsType>
<ItemTextsTypeDesc>description21</ItemTextsTypeDesc>
<ItemTextsLine>3</ItemTextsLine>
</ItemText>
<ItemText>
<ItemTextsType>type2</ItemTextsType>
<ItemTextsTypeDesc>description22</ItemTextsTypeDesc>
<ItemTextsLine>4</ItemTextsLine>
</ItemText>
</ItemTexts>
</Item>
<Item>
<ItemTexts>
<ItemText>
<ItemTextsType>type3</ItemTextsType>
<ItemTextsTypeDesc>description31</ItemTextsTypeDesc>
<ItemTextsLine>1</ItemTextsLine>
</ItemText>
<ItemText>
<ItemTextsType>type3</ItemTextsType>
<ItemTextsTypeDesc>description32</ItemTextsTypeDesc>
<ItemTextsLine>2</ItemTextsLine>
</ItemText>
<ItemText>
<ItemTextsType>type2</ItemTextsType>
<ItemTextsTypeDesc>description21</ItemTextsTypeDesc>
<ItemTextsLine>3</ItemTextsLine>
</ItemText>
<ItemText>
<ItemTextsType>type2</ItemTextsType>
<ItemTextsTypeDesc>description22</ItemTextsTypeDesc>
<ItemTextsLine>4</ItemTextsLine>
</ItemText>
</ItemTexts>
</Item>
</Items>
我在每个项目上都使用 xsl 运行，例如:
I run with xsl on each Item like :
<xsl:for-each select="Items/Item">
我需要一个示例，说明如何将 <ItemText> 按 <ItemTextsType> 为每个 <Item> 单独分组所以结果会是这样的:
I need an example of how to group <ItemText> by <ItemTextsType> individually for each <Item>so the outcome will be like :
对于本例中的第一个 <Item>:
For first <Item> in this example :
type1
description11
description12
type2
描述21
描述22
对于本例中的第二个Item:
type3
description31
description32
type2
描述21
描述22
当然，我会将结果安排在如下表格中:
of course I will arrange the outcome in a table like :
<table width="100%" border="1" style="display: block;">
<tbody>
<tr>
<td id="SelectedRowLinkageContents">
<table width="100%" dir="ltr">
<tbody>
<tr style="background-color: #507CD1; text-align: center">
<td colspan="3" style="font: bold; color: white">
Item1
</td>
</tr>
<tr>
<td style="height: 35px; font: bold; color: #507CD1;">
type1
</td>
</tr>
<tr>
<td>
desription11
</td>
</tr>
<tr>
<td>
desription12
</td>
</tr>
<tr>
<td style="height: 35px; font: bold; color: #507CD1;">
type2
</td>
</tr>
<tr>
<td>
desription21
</td>
</tr>
<tr>
<td>
desription22
</td>
</tr>
<tr>
<td>
desription23
</td>
</tr>
</tbody>
</table>
<table width="100%" dir="ltr">
<tbody>
<tr style="background-color: #507CD1; text-align: center">
<td colspan="3" style="font: bold; color: white">
Item2
</td>
</tr>
<tr>
<td style="height: 35px; font: bold; color: #507CD1;">
type1
</td>
</tr>
<tr>
<td>
desription11
</td>
</tr>
<tr>
<td>
desription12
</td>
</tr>
<tr>
<td style="height: 35px; font: bold; color: #507CD1;">
type2
</td>
</tr>
<tr>
<td>
desription21
</td>
</tr>
<tr>
<td>
desription23
</td>
</tr>
</tbody>
</table>
<table width="100%" dir="ltr">
<tbody>
<tr style="background-color: #507CD1; text-align: center">
<td colspan="3" style="font: bold; color: white">
Item3
</td>
</tr>
<tr>
<td style="height: 35px; font: bold; color: #507CD1;">
type1
</td>
</tr>
<tr>
<td>
desription11
</td>
</tr>
<tr>
<td>
desription12
</td>
</tr>
<tr>
<td style="height: 35px; font: bold; color: #507CD1;">
type2
</td>
</tr>
<tr>
<td>
desription21
</td>
</tr>
<tr>
<td>
desription23
</td>
</tr>
</tbody>
</table>
</td>
</tr>
</tbody>
</table>
关键是每个 <Item> 都有单独的分组到它自己的 <table> 和内部 <table>code> 有按 <ItemTextsType>
The point is that there is separate grouping for each <Item> into it's own <table> and inside that <table> there is groupping by <ItemTextsType>
我尝试过类似的东西
<xsl:key name="item-texts-type" match="ItemText" use="ItemTextsType" />
<xsl:for-each select="ItemTexts/ItemText[count(. | key('item-texts-type', ItemTextsType)[1]) = 1]">
<xsl:sort select="ItemTextsType" />
<tr>
<td style ="height:35px;font: bold; color:#507CD1;">
<xsl:value-of select="ItemTextsType" />
</td>
</tr>
<xsl:for-each select="key('item-texts-type', ItemTextsType)">
<tr>
<td>
<xsl:value-of select="ItemTextsTypeDesc" />
</td>
</tr>
</xsl:for-each>
</xsl:for-each>
但它只适用于非重复节点(如果只有一个<Item>它会正常工作).我无法更改 xml，因为它来自客户.
but it only work on non repetitive nodes (if there were only one <Item>it would work fine).I can't change xml because it comes from customer .
请帮帮我，我需要它尽快.
Please help me , I need it ASAP .
谢谢！！！！
推荐答案
由于一些差异，仍然很难说出所需的解决方案 - 例如，您的输入 XML 有 4 个 <Item> 元素，但您想要的输出只考虑其中的 3 个.此外，您所需输出中的一些描述与其在输入 XML 文档中的预期位置不匹配.
It's still difficult to tell what the desired solution is due to some discrepancies - for instance, your input XML has 4 <Item> elements, but your desired output only takes 3 of them into account. Additionally, several descriptions in your desired output do not match up with their expected location in the input XML document.
也就是说，如果我们专注于您所说的所需解决方案:
That said, if we focus on your stated desired solution:
"关键是每个 <Item> 都有单独的分组到它是自己的 <table> 并且在那个 <table> 里面有分组<ItemTextsType>"
...那么这应该会让你朝着正确的方向前进.
...then this ought to get you in the right direction.
当这个 XSLT:
<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
version="1.0">
<xsl:output omit-xml-declaration="yes" indent="yes" />
<xsl:strip-space elements="*" />
<xsl:key
name="kItemTextByType"
match="ItemText"
use="concat(generate-id(ancestor::Item[1]), '+', ItemTextsType)" />
<xsl:template match="node()|@*">
<xsl:copy>
<xsl:apply-templates select="node()|@*" />
</xsl:copy>
</xsl:template>
<xsl:template match="/*">
<table width="100%" border="1" style="display: block;">
<tbody>
<tr>
<td id="SelectedRowLinkageContents">
<xsl:apply-templates />
</td>
</tr>
</tbody>
</table>
</xsl:template>
<xsl:template match="Item">
<table width="100%" dir="ltr">
<tbody>
<tr style="background-color: #507CD1; text-align: center">
<td colspan="3" style="font: bold; color: white">
<xsl:value-of select="concat('Item', position())" />
</td>
</tr>
<xsl:apply-templates
select="ItemTexts/ItemText[
generate-id() =
generate-id(
key(
'kItemTextByType',
concat(generate-id(current()), '+', ItemTextsType)
)[1]
)
]">
<xsl:sort select="ItemTextsType" />
</xsl:apply-templates>
</tbody>
</table>
</xsl:template>
<xsl:template match="ItemText">
<tr>
<td style="height: 35px; font: bold; color: #507CD1;">
<xsl:value-of select="ItemTextsType" />
</td>
</tr>
<xsl:for-each
select="key(
'kItemTextByType',
concat(
generate-id(ancestor::Item[1]),
'+',
ItemTextsType
)
)"
>
<xsl:sort select="ItemTextsTypeDesc" />
<tr>
<td>
<xsl:value-of select="ItemTextsTypeDesc" />
</td>
</tr>
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>
...应用于提供的输入 XML:
<?xml version="1.0" encoding="UTF-8"?>
<Items>
<Item>
<ItemTexts>
<ItemText>
<ItemTextsType>type1</ItemTextsType>
<ItemTextsTypeDesc>description11</ItemTextsTypeDesc>
<ItemTextsLine>1</ItemTextsLine>
</ItemText>
<ItemText>
<ItemTextsType>type1</ItemTextsType>
<ItemTextsTypeDesc>description12</ItemTextsTypeDesc>
<ItemTextsLine>2</ItemTextsLine>
</ItemText>
<ItemText>
<ItemTextsType>type2</ItemTextsType>
<ItemTextsTypeDesc>description21</ItemTextsTypeDesc>
<ItemTextsLine>3</ItemTextsLine>
</ItemText>
<ItemText>
<ItemTextsType>type2</ItemTextsType>
<ItemTextsTypeDesc>description22</ItemTextsTypeDesc>
<ItemTextsLine>4</ItemTextsLine>
</ItemText>
</ItemTexts>
</Item>
<Item>
<ItemTexts>
<ItemText>
<ItemTextsType>type1</ItemTextsType>
<ItemTextsTypeDesc>description11</ItemTextsTypeDesc>
<ItemTextsLine>1</ItemTextsLine>
</ItemText>
<ItemText>
<ItemTextsType>type1</ItemTextsType>
<ItemTextsTypeDesc>description12</ItemTextsTypeDesc>
<ItemTextsLine>2</ItemTextsLine>
</ItemText>
<ItemText>
<ItemTextsType>type2</ItemTextsType>
<ItemTextsTypeDesc>description21</ItemTextsTypeDesc>
<ItemTextsLine>3</ItemTextsLine>
</ItemText>
<ItemText>
<ItemTextsType>type2</ItemTextsType>
<ItemTextsTypeDesc>description22</ItemTextsTypeDesc>
<ItemTextsLine>4</ItemTextsLine>
</ItemText>
</ItemTexts>
</Item>
<Item>
<ItemTexts>
<ItemText>
<ItemTextsType>type1</ItemTextsType>
<ItemTextsTypeDesc>description11</ItemTextsTypeDesc>
<ItemTextsLine>1</ItemTextsLine>
</ItemText>
<ItemText>
<ItemTextsType>type1</ItemTextsType>
<ItemTextsTypeDesc>description12</ItemTextsTypeDesc>
<ItemTextsLine>2</ItemTextsLine>
</ItemText>
<ItemText>
<ItemTextsType>type2</ItemTextsType>
<ItemTextsTypeDesc>description21</ItemTextsTypeDesc>
<ItemTextsLine>3</ItemTextsLine>
</ItemText>
<ItemText>
<ItemTextsType>type2</ItemTextsType>
<ItemTextsTypeDesc>description22</ItemTextsTypeDesc>
<ItemTextsLine>4</ItemTextsLine>
</ItemText>
</ItemTexts>
</Item>
<Item>
<ItemTexts>
<ItemText>
<ItemTextsType>type3</ItemTextsType>
<ItemTextsTypeDesc>description31</ItemTextsTypeDesc>
<ItemTextsLine>1</ItemTextsLine>
</ItemText>
<ItemText>
<ItemTextsType>type3</ItemTextsType>
<ItemTextsTypeDesc>description32</ItemTextsTypeDesc>
<ItemTextsLine>2</ItemTextsLine>
</ItemText>
<ItemText>
<ItemTextsType>type2</ItemTextsType>
<ItemTextsTypeDesc>description21</ItemTextsTypeDesc>
<ItemTextsLine>3</ItemTextsLine>
</ItemText>
<ItemText>
<ItemTextsType>type2</ItemTextsType>
<ItemTextsTypeDesc>description22</ItemTextsTypeDesc>
<ItemTextsLine>4</ItemTextsLine>
</ItemText>
</ItemTexts>
</Item>
</Items>
...想要的结果是(我认为)产生的:
<table width="100%" border="1" style="display: block;">
<tbody>
<tr>
<td id="SelectedRowLinkageContents">
<table width="100%" dir="ltr">
<tbody>
<tr style="background-color: #507CD1; text-align: center">
<td colspan="3" style="font: bold; color: white">Item1</td>
</tr>
<tr>
<td style="height: 35px; font: bold; color: #507CD1;">type1</td>
</tr>
<tr>
<td>description11</td>
</tr>
<tr>
<td>description12</td>
</tr>
<tr>
<td style="height: 35px; font: bold; color: #507CD1;">type2</td>
</tr>
<tr>
<td>description21</td>
</tr>
<tr>
<td>description22</td>
</tr>
</tbody>
</table>
<table width="100%" dir="ltr">
<tbody>
<tr style="background-color: #507CD1; text-align: center">
<td colspan="3" style="font: bold; color: white">Item2</td>
</tr>
<tr>
<td style="height: 35px; font: bold; color: #507CD1;">type1</td>
</tr>
<tr>
<td>description11</td>
</tr>
<tr>
<td>description12</td>
</tr>
<tr>
<td style="height: 35px; font: bold; color: #507CD1;">type2</td>
</tr>
<tr>
<td>description21</td>
</tr>
<tr>
<td>description22</td>
</tr>
</tbody>
</table>
<table width="100%" dir="ltr">
<tbody>
<tr style="background-color: #507CD1; text-align: center">
<td colspan="3" style="font: bold; color: white">Item3</td>
</tr>
<tr>
<td style="height: 35px; font: bold; color: #507CD1;">type1</td>
</tr>
<tr>
<td>description11</td>
</tr>
<tr>
<td>description12</td>
</tr>
<tr>
<td style="height: 35px; font: bold; color: #507CD1;">type2</td>
</tr>
<tr>
<td>description21</td>
</tr>
<tr>
<td>description22</td>
</tr>
</tbody>
</table>
<table width="100%" dir="ltr">
<tbody>
<tr style="background-color: #507CD1; text-align: center">
<td colspan="3" style="font: bold; color: white">Item4</td>
</tr>
<tr>
<td style="height: 35px; font: bold; color: #507CD1;">type2</td>
</tr>
<tr>
<td>description21</td>
</tr>
<tr>
<td>description22</td>
</tr>
<tr>
<td style="height: 35px; font: bold; color: #507CD1;">
type3</td>
</tr>
<tr>
<td>description31</td>
</tr>
<tr>
<td>description32</td>
</tr>
</tbody>
</table>
</td>
</tr>
</tbody>
</table>
...在 HTML 页面中呈现时如下所示:
这篇关于通过xslt1中的xml元素对重复节点进行xsl分组的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！