本文介绍了如何使用后面的VB代码添加GridView的ItemTemplate的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
大家好.
有人可以帮我做我的密码吗?
我想在gridview中创建一个动态列.
我的样本:
Good day to everyone.
can anybody help me with my codes?
I want to create a dynamic column in gridview..
My sample:
<asp:GridView ID="GridView1" runat="server" AutoGenerateColumns="False" DataKeyNames="EmployeeID" DataSourceID="ObjectDataSource1">
<columns>
<asp:BoundField DataField="LastName" HeaderText="LastName" SortExpression="LastName" />
<asp:BoundField DataField="FirstName" HeaderText="FirstName" SortExpression="FirstName" />
<asp:BoundField DataField="Title" HeaderText="Title" SortExpression="Title" />
<asp:BoundField DataField="HireDate" HeaderText="HireDate" SortExpression="HireDate" />
</columns>
我的问题是如何创建动态列.意思是说< column>内部的所有数据都是将在后台代码中动态创建.它可以是BoundField,也可以是ItemTemplate(我更喜欢ItemTemplate),最终代码是
My problem is how to create a dynamic column. Meaning to say all data inside <column> will be created dynamically at code-behind. It can be either BoundField or by ItemTemplate (i prefer ItemTemplate please) the final code would be
<asp:GridView ID="GridView1" runat="server" AutoGenerateColumns="False" DataKeyNames="EmployeeID" DataSourceID="ObjectDataSource1">
<column>
...all code here will be created at code behind...
</column>
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