问题描述
这是在 scala 2.13 中,为什么有时无法显式调用类型类?:
以下代码可以正常编译:
The following code can compile properly:
import shapeless._
import record._
import syntax.singleton._
val book =
("author" ->> "Benjamin Pierce") ::
("title" ->> "Types and Programming Languages") ::
("id" ->> 262162091) ::
("price" ->> 44.11) ::
HNil
val v1 = book.values
assert(v1.head == "Benjamin Pierce")
case class HasValues[T <: HList: TypeTag](v: T) {
// def vs(implicit v: Values[T]) = v // doesn't work
def vs(implicit v: Values[T]): Values.Aux[T, v.Out] = v // works
}
val _vs = HasValues(book).vs
val v2 = book.values(_vs)
assert(v2.head == "Benjamin Pierce")
虽然以下代码在编译时和运行时在语法上都相同,但编译失败:
While the following code, which is syntactically identical in both compile time and run time, failed the compilation:
import shapeless._
import record._
import syntax.singleton._
val book =
("author" ->> "Benjamin Pierce") ::
("title" ->> "Types and Programming Languages") ::
("id" ->> 262162091) ::
("price" ->> 44.11) ::
HNil
val v1 = book.values
assert(v1.head == "Benjamin Pierce")
case class HasValues[T <: HList: TypeTag](v: T) {
type TT = T
}
val hv = HasValues(book)
val _vs = implicitly[Values[hv.TT]]
val _vs2: Values.Aux[hv.TT, _vs.Out] = _vs
val v2 = book.values(_vs2)
assert(v2.head == "Benjamin Pierce")
结果:
[Error] /home/peng/git-spike/scalaspike/common/src/test/scala/com/tribbloids/spike/shapeless_spike/RecordProblem2.scala:41: could not find implicit value for parameter c: shapeless.ops.hlist.IsHCons[com.tribbloids.spike.shapeless_spike.RecordProblem2._vs2.Out]
one error found
此外,以下行似乎非常样板.理想情况下,我认为编译器应该能够弄清楚自己的改进,考虑到这完全是一个向上的:
In addition, the following line seems to be very boilerplate-y. Ideally I think the compiler should be able to figure out the refinement on itself, considering that this is totally an upcast:
val _vs = implicitly[Values[hv.TT]]
val _vs2: Values.Aux[hv.TT, _vs.Out] = _vs
为什么第二个编译失败,另外,如何去掉那个样板鸭类型声明?(当然,不用修改HasValues类的签名)
Why the second one failed the compilation, and furthermore, how to get rid of that boilerplate duck type declaration? (Of course, without modifying the signature of the class HasValues)
推荐答案
隐式
可能会破坏类型细化.改用 shapeless.the
.
implicitly
can corrupt type refinements. Use shapeless.the
instead.
代码
val hv = HasValues(book)
val _vs = the[Values[hv.TT]]
val _vs2: Values.Aux[hv.TT, _vs.Out] = _vs
val v2 = book.values(_vs2)
assert(v2.head == "Benjamin Pierce")
编译.
https://typelevel.org/blog/2014/01/18/implicitly_existential.html
还有
val hv = HasValues(book)
val _vs2 = the[Values[hv.TT]]
val v2 = book.values(_vs2)
assert(v2.head == "Benjamin Pierce")
和
val hv = HasValues(book)
val v2 = book.values
assert(v2.head == "Benjamin Pierce")
编译.
另外注意可以替换
def vs(implicit v: Values[T]): Values.Aux[T, v.Out] = v
与
def vs(implicit v: Values[T]): v.type = v
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