如何用Rust封装现有的C函数或如何从Rust调用C函数?

问题描述

我有现有的C代码及其标头，我需要从Rust调用C代码.我尝试了很多方法并参考了文档，但我不知道如何将其应用于代码.我面临着将C函数转换为Rust的困难.请帮我举一些例子，以便我容易理解.

I have existing C code and its header and I need to call the C code from Rust. I tried it many ways and referred to documents but I didn't understand how to apply that to my code. I'm facing difficulties converting C functions into Rust. Please help me with some examples so that I can understand easily.

我尝试使用Rust书中给出的示例以及其他网站示例，但是没有资源对此提供更多详细信息.

I tried to use the examples given in the Rust book and other website examples, but no resource has more details on this.

C_code.h

void ifx_vec_init_r(ifx_Vector_R_t* vector,
                    ifx_Float_t* d,
                    uint32_t length);

void ifx_vec_init_c(ifx_Vector_C_t* vector,
                    ifx_Complex_t* d,
                    uint32_t length);

void ifx_vec_rawview_r(ifx_Vector_R_t* vector,
                       ifx_Float_t* d,
                       uint32_t length,
                       uint32_t stride);

void ifx_vec_sub_r(const ifx_Vector_R_t* v1,
                   const ifx_Vector_R_t* v2,
                   ifx_Vector_R_t* result);

我想在Rust中调用上述所有函数，但是我无法理解如何启动或更改.包装此C代码时，我们需要注意什么?有哪些可用的方法?

I want to call all above functions in Rust, but I am not able to understand how to start or how to change. What and all we to take care to wrap this C code? What are the ways available?

推荐答案

如果您尝试从Rust调用C代码，则需要创建FFI绑定，就像某些人在评论中提到的那样.

If you're trying to call C code from Rust, you need to create FFI bindings as some people have mentioned in the comments.

但是，通常最好通过 rust-bindgen ，它会自动生成绑定并包括测试以确保结果的大小正确，对齐等.创建大小错误的类型非常容易，这在编译时不会给您任何警告，并且可以导致不确定的行为，除非您使用bindgen为它们生成测试.

However, it is usually best to do this via rust-bindgen, which automatically generates the bindings and includes tests to make sure that the results are properly sized, aligned, etc. It is very easy to create a type with an incorrect size, which will give you no warning at compile-time and can cause undefined behavior unless you generate tests for them with bindgen.

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