如果我在末尾添加新行'\ n'，scanf的工作原理

问题描述

#include <stdio.h>
int main(){

    int a,b,c;

    scanf("%d%d%d\n",&a,&b,&c);
    printf("%d %d %d",a,b,c);

    return 0;
}

看我要输入3个输入并打印3个输出...但是当我在scanf函数的末尾添加新行时，我必须给出4个输入才能得到3个输出(我得到前3个作为输入)... scanf在这里如何工作?在这种情况下:

Look I am taking 3 inputs and printing 3 outputs... But as I added a new line at the end of the scanf function I have to give 4 inputs to get 3 outputs(I get the first 3 I give as input)... How scanf works here?And in this case:

#include <stdio.h>

int main(){

    double n[2][5]; int i,j;

    for (i=0;i<=1;i++){

        for(j=0;j<=4;j++){

            scanf("%lf\n",&n[i][j]);
            printf("Class=%d Roll=%d Marks=%lf\n",i+6,j+1,n[i][j]);

        }
    }

    return 0;
}

看起来我必须给出11个输入才能获得10个输出...并且每当我输入一个输入时，我都会得到前一个输入作为输出... scanf在这里如何工作?

Look I have to give 11 inputs to get the 10 outputs... And each time I give a input I get the previous input as an output... How scanf is working here?

推荐答案

scanf格式的白色字符与输入中的白色字符序列匹配，直到非白色字符为止.

A white character in scanf format matches a sequence of white characters in the input until a non-white character.

换行符是一个白色字符，这说明了程序的行为.这意味着，如果您的scanf格式以换行符终止，则它不会结束，直到在最后一次解析的输入之后看到另一个非空白字符为止.

Newline is a white character and this explains the behavior of your program. Meaning that if your scanf format terminates by a newline, it does not finish until it sees an additional non-blank character after the last parsed input.

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