使用内存中的字节数组(没有物理文件)创建 Java File 对象(或等效对象)

问题描述

我想在内存中创建一个 Java File 对象(不创建物理文件)并用字节数组填充其内容.

I want to create a Java File object in memory (without creating a physical file) and populate its content with a byte array.

这能做到吗?

想法是将它传递给 Spring InputStreamSource.我正在尝试下面的方法，但它返回说字节数组不包含文件名.".

The idea is to pass it to a Spring InputStreamSource. I'm trying the method below, but it returns saying "the byte array does not contain a file name.".

MimeMessage message = mailSender.createMimeMessage();
MimeMessageHelper helper = new MimeMessageHelper(message);
helper.setFrom("[email protected]", "xyz");
helper.setTo(email);
helper.setText(body,true);
helper.setSubject(subject);
helper.addInline("cImage",
        new InputStreamResource(new ByteArrayInputStream(imageByteArr)));

mailSender.send(message);

推荐答案

你能粘贴完整的堆栈跟踪吗?没有内存中"文件这样的东西.使用 ByteArrayInputStream 应该就足够了.

Can you paste the full stack trace? There is no such thing as an "in memory" file. Using a ByteArrayInputStream should be sufficient.

你需要实现Resource#getFilename().请尝试以下操作:

You need to implement Resource#getFilename(). Try the following:

helper.addInline("cImage", new ByteArrayResource(imageByteArr){
            @Override
            public String getFilename() {
                return fileName;
            }
        });

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