对于大型字典来说，架子太慢了，我该怎么做来提高性能？

问题描述

我使用python存储一个表，我需要持久化。

基本上我把表作为字典字符串存储到数字。

  c：string 
 
 $ <$>  
 code>键值对，我建议使用JSON原生存储解决方案，例如 。它有一个奇妙的Python API，。 MongoDB本身是轻量级和令人难以置信的快，json对象本身将是Python中的字典。这意味着您可以使用 string 键作为对象ID，允许压缩存储和快速查找。
 
 
 
作为代码容易的示例，请参阅以下内容：
  d = {'string1'：1，'string2 '：2，'string3'：3} 
从pymongo import Connection 
 conn = Connection（）
 db = conn ['example-database'] 
 collection = db [ example-collection'] 
 for string，num in d.items（）：
 collection.save（{'_ id'：string，'value'：num}）
＃testing 
 newD = {} 
 for obj in collection.find（）：
 newD [obj ['_ id']] = obj ['value'] 
 print newD 
＃输出为：{u'string2'：2，u'string3'：3，u'string1'：1} 
  
 
 $ b b 
你只需要从unicode转换回来，这很简单。
 
I am storing a table using python and I need persistence.
Essentially I am storing the table as a dictionary string to numbers. And the whole is stored with shelve
self.DB=shelve.open("%s%sMoleculeLibrary.shelve"%(directory,os.sep),writeback=True)
I use writeback to True as I found the system tends to be unstable if I don't.
After the computations the system needs to close the database, and store it back. Now the database (the table) is about 540MB, and it is taking ages. The time exploded after the table grew to about 500MB. But I need a much bigger table. In fact I need two of them.
I am probably using the wrong form of persistence. What can I do to improve performance?
 解决方案 
For storing a large dictionary of string : number key-value pairs, I'd suggest a JSON-native storage solution such as MongoDB. It has a wonderful API for Python, Pymongo. MongoDB itself is lightweight and incredibly fast, and json objects will natively be dictionaries in Python. This means that you can use your string key as the object ID, allowing for compressed storage and quick lookup.
As an example of how easy the code would be, see the following:
d = {'string1' : 1, 'string2' : 2, 'string3' : 3}
from pymongo import Connection
conn = Connection()
db = conn['example-database']
collection = db['example-collection']
for string, num in d.items():
    collection.save({'_id' : string, 'value' : num})
# testing
newD = {}
for obj in collection.find():
    newD[obj['_id']] = obj['value']
print newD
# output is: {u'string2': 2, u'string3': 3, u'string1': 1}
You'd just have to convert back from unicode, which is trivial.
                        
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