问题描述
我有两个表A和B.我想要表A中的所有记录,其中
Sum(A.Duration)!= Sum(B.Duration)and A.Ecode = B.ECode.我正在尝试编写查询,但无法在where子句中使用聚合函数.
表A具有与列相同的Ecode,Ename,Duration,表B也具有相同的列名称.
请帮助我,谢谢.
I have two tables A and B. I want all the records from table A where
Sum(A.Duration)!=Sum(B.Duration)and A.Ecode=B.ECode.I am trying to write the query but getting that cant use aggregate function in where clause.
Table A have Ecode,Ename,Duration as Columns and Table B also have the same column name.
Please help me and thanks in advance.
推荐答案
SUM(A.Duration)
将在表A Duration列中添加所有记录,
will add all the records in the table A Duration column,
SUM(B.Duration)
将对表B执行相同操作
因此,要么获取所有记录(如果总数相同),要么不获取所有记录(如果总数不同)
无论哪种方式,您的查询都有点愚蠢,而且我不敢相信那是您真正想要做的.
will do the same for table B
So either you should get all the records (if the totals are the same) or none of them (if the totals are different)
Either way, your query is a little silly, and I can''t believe that is what you actually wanted to do.
Sum(A.Duration)!=Sum(B.Duration)
只需使用子查询即可.
Just use subqueries..
(select sum(duration) from tableA) != (select sum(duration) from tableB)
最好..
all the best..
Select * from TablaA A, TableB B
Where A.Ecode=B.ECode
group by ............ having Sum(A.Duration)!=Sum(B.Duration)
这篇关于在where子句中聚合函数.的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!