本文介绍了加入2个子查询的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
如果有任何帮助,我将不胜感激.我正在尝试对2个子查询执行连接,但它一直说'IntEncTracking.EncounterList.ClaimId'在选择列表中无效,因为它既不包含在聚合函数中也不在GROUP BY子句中,但是我已经尝试用el和q2进行排位赛,但无济于事.任何建议将不胜感激.
I would appreciate any assistance w/this. I'm trying to perform a join on 2 subqueries, but it keeps saying the 'IntEncTracking.EncounterList.ClaimId' is invalid in the select list because it is not contained in either an aggregate function or the GROUP BY clause, but I've tried qualifying it with an el and q2, to no avail. Any advice would be greatly appreciated.
Select * from (Select distinct ClaimId
, LineNum
, 0 as EncounterLineNum
, EncounterType
, InternalICN
, PreviousDpwICN
, 0 as ClaimFrequencyCd
, EncounterPeriod
, 2 as StatusCd
, BypassReason
, null as EncounterFileNm
,@SweepId as SweepId
from IntEncTracking.EncounterList
where bypassflag = 1) as q1
join
( Select ClaimId
, 0 as LineNum
, 0 as EncounterLineNum
, EncounterType
, InternalICN
, PreviousDpwICN
, max(ClaimFreqCd) as ClaimFreqCd
, max(EncounterPeriod) as EncounterPeriod
, case when exists (select 'x'
from IntEncTracking.EncounterList el1
where el1.claimid = claimid
and BypassFlag = 0) then 1
else 2
end stscd
, case when @RunType = 'Initial' then 100 else 300 end as [StatusReasonCd]
, null as EncounterFileNm
, @SweepId as SweepId
from IntEncTracking.EncounterList el
where BypassFlag = 0) as q2
on q1.ClaimId = q2.ClaimId and
q1.LineNum = q2.LineNum and
q1.EncounterLineNum = q2.EncounterLineNum and
q1.EncounterType = q2.EncounterType and
q1.InternalICN = q2.InternalICN
group by q1.ClaimId, q1.EncounterType, q1.InternalICN, q1.PreviousDpwICN
order by q2.ClaimId, q2.LineNum, q2.EncounterLineNum, q2.EncounterType, q2.InternalICN
推荐答案
我总是这样做
;with EncounterValues as(
SELECT
CommonValueOrId,
ect..
FROM
IntEntTracking.EncountrList
)
, EncounterFileNums as(
SELECT
CommonValueOrId,
ect..
FROM
IntEncTracking.EncounterList
)
SELECT
ev.AnyField,
efn.AnyField
FROM
EncounterValues ev
LEFT JOIN EncounterFileNums efn
ON ev.CommonValueOrId = evn.CommonValueOrId
不确定这样做的含义是什么,但是如果您在挣扎中,也许值得一试.
Not sure what the implications of doing it this way is but might be worth giving it a go if you're struggling.
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