问题描述
我知道我能做到这一点:
I know I can do this:
set=("1 2 3" "4 5 6")
for subset in "${set[@]}"
do
for element in $subset
do
echo $element
done
done
1 2 3 4 5 6将顺序打印。不过,我可以的不可以做到这一点:
set="(1 2 3) (4 5 6)"
for subset in $set
do
echo ${subset[2]}
done
我要打印3 6.为什么我想这样做的原因是,我想有机会获得任何元素我要迭代的迭代,而不是逐个期间访问。这就是为什么我试图把阵列内的报价,而不是把报价一大阵里面。有没有办法做到这一点?
谢谢,
I want to print 3 6. The reason why I want to do this is that I want to have access to whichever element I want to access during iteration instead of iterating one by one. That's why I try to put arrays inside quotes instead of putting quotes inside a big array. Is there any way to do this?Thanks,
推荐答案
不幸的是,我不认为bash的支持多维数组,这听起来像你在找什么。您可以从庆典本身的一点帮助,像这样进行模拟:
Unfortunately, I don't think bash supports multi-dimentional arrays, which sounds like what you're looking for. You can simulate it with a little help from bash itself like so:
x=()
x+=("1,2,3")
x+=("4,5,6")
for val in ${x[@]}; do
subset=($(echo $val | tr ',' ' '))
echo ${subset[2]}
done
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