并排显示实心和空心的星号正方形

问题描述

我当前正在尝试显示一个实心的星号正方形和一个空心的星号:

I'm currently trying to display a filled asterisk square and a hollow asterisk :

********** **********
********** *        *
********** *        *
********** *        *
********** **********

相反，我得到以下输出:

Instead, I'm getting this output:

**********
**********
**********
**********
**********
**********
*        *
*        *
*        *
**********

我不太确定如何使其并排而不是上下移动.我是否必须将空心嵌套循环放入填充循环内，还是必须做其他事情?这是我的代码:

I'm not so sure how to make it side by side instead of up and down. Do I have to put the hollow nested loop inside the filled loop or do I have to do something else? Here is my code:

public class doubleNestedLoops {
    public static void main(String[] args) {
        //Filled Square
        for (int i = 1; i <= 5; i++) {
            for (int j = 1; j <= 10; j++) {
                System.out.print("*");
            }
            System.out.println();
        }

        //Hollow Square
        for (int j = 1; j <= 5; j++) {
            for (int i = 1; i <= 10; i++) {
                if (j == 1 || j == 5 || i == 1 || i == 10) {
                    System.out.print("*");
                } else {
                    System.out.print(" ");
                }
            }
            System.out.println();
        }
    }
}

推荐答案

John Martinez的回答很好，但是效率低下.我将逐步将您的代码放在下面，并对其进行了修改:

John Martinez' answer works fine, but it's a little inefficient. I'll put a step by step below your code, which I revamped:

public class Main {
    public static void main(String[] args) {
        //Both Squares
        StringBuilder filledLine = new StringBuilder(10);
        StringBuilder hollowLine = new StringBuilder(10);
        for (int i = 1; i <= 5; i++) {
            for (int j = 1; j <= 10; j++) {
                filledLine.append("*");
                if (i == 1 || i == 5 || j == 1 || j == 10) {
                    hollowLine.append("*");
                } else {
                    hollowLine.append(" ");
                }
            }
            System.out.println(filledLine + " " + hollowLine);
            filledLine.delete(0, filledLine.length());
            hollowLine.delete(0, hollowLine.length());
        }
    }
}

第1步:将您的两个循环转换为一个循环.这是因为一旦创建新行，便无法在同一行上打印.

Step 1: Convert your two loops to one loop. This is because you cannot print on the same line once you've made a new line.

Step2:因为我们将在循环中使用字符串，所以使用 StringBuffer 效率更高，因此我们不会不断创建新的字符串

Step2: Because we'll be using Strings in a loop, it's more efficient to use a StringBuffer, so we don't constantly make new strings

第3步:将逻辑的所有输出写入缓冲区，而不是控制台.

Step 3: Write all of the output from your logic to the buffers instead of the console.

第4步:在填充缓冲区时，一次只打印一行.

Step 4: Print the buffers one line at a time, as we fill them.

第5步:获利！

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