在新的stdClass中声明一个匿名函数

问题描述

只是想知道为什么这样的东西行不通:

Just wondering why something like this doesn't work:

public function address($name){
    if(!isset($this->addresses[$name])){
        $address = new stdClass();
        $address->city = function($class = '', $style = ''){
            return $class;
        };
        $this->addresses[$name] = $address;
    }
    return $this->addresses[$name];
}

像echo $class->address('name')->city('Class')那样调用它应该只回显Class，但是我却得到Fatal error: Call to undefined method stdClass::city()

Calling it like echo $class->address('name')->city('Class') should just echo Class, however I get Fatal error: Call to undefined method stdClass::city()

我可以找到一种更好的方法来执行此操作，因为这会变得很混乱，但是我想知道那里可能做错了什么，或者PHP是否不支持此操作以及原因.

I can find a better way to do this, because this will get messy, but I'm wondering what I might be doing wrong there, or if PHP doesn't support this and why.

推荐答案

调用致命错误Call to undefined method stdClass::city()时PHP是正确的，因为对象$class->address('name') 没有方法 city.Intead，此对象具有属性 city，它是Closure类的实例( http ://www.php.net/manual/zh/class.closure.php )您可以验证以下内容:var_dump($class->address('name')->city)

PHP is right when invoke fatal error Call to undefined method stdClass::city() because object $class->address('name') has no method city.Intead, this object has property city which is instance of Closure Class (http://www.php.net/manual/en/class.closure.php)You can verify this: var_dump($class->address('name')->city)

我发现调用此匿名函数的方法是:

I found the way to call this anonymous function is:

$closure = $class->address('name')->city;
$closure('class');

希望这会有所帮助！

这篇关于在新的stdClass中声明一个匿名函数的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！