本文介绍了将bash变量传递给jq的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！
问题描述
我写了一个脚本来从file.json中检索某些值.如果我将值提供给jq select，它将起作用，但是该变量似乎不起作用(或者我不知道如何使用它).
I have written a script to retrieve certain value from file.json. It works if I provide the value to jq select, but the variable doesn't seem to work (or I don't know how to use it).
#!/bin/sh
#this works ***
projectID=$(cat file.json | jq -r '.resource[] | select(.username=="[email protected]") | .id')
echo "$projectID"
[email protected]
#this does not work *** no value is printed
projectID=$(cat file.json | jq -r '.resource[] | select(.username=="$EMAILID") | .id')
echo "$projectID"
推荐答案
还考虑将shell变量(EMAILID)作为jq变量(为便于说明，此处也称为EMAILID)传递:
Consider also passing in the shell variable (EMAILID) as a jq variable (here also EMAILID, for the sake of illustration):
projectID=$(cat file.json |
jq -r --arg EMAILID "$EMAILID" '
.resource[]
| select(.username==$EMAILID)
| .id')
后记
出于记录目的，另一种可能性是使用jq的env函数访问环境变量.例如，考虑以下bash命令序列:
Postscript
For the record, another possibility would be to use jq's env function for accessing environment variables. For example, consider this sequence of bash commands:
[email protected] # not exported
EMAILID="$EMAILID" jq -n 'env.EMAILID'
输出为JSON字符串:
The output is a JSON string:
"[email protected]"
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