将python列表转换为字典

问题描述

我正在尝试将我的列表转换为python中的字典。我有列表l

  l = ['a'，'b'，'c'，'d'] 
  

，我想将其转换为字典d

  d ['a'] = [] 
d ['b'] = [] 
d ['c'] = [] 
d ['d'] = [] 
  

我正在尝试

  for i in range（0，len（l））：
d [i] [0] = l（i）
  pre> 
 
 
但这不行。谢谢
解决方案
保持它比这更简单，你想循环你的列表，然后分配你的迭代器 i （这将是您的列表中的每个值）作为每个字典条目的键。 
  l = ['a'，'b'，'c'，'d'] 
 
d = {} 
对于我在l：
d [i] = [] 
 
 
打印（d）＃{'a'：[]，'c '：[]，'b'：[]，'d'：[]} 
  
以上理解，您现在可以将其简化为一行：
  {k：[] for k in l} 
  
以上称为字典理解。您可以阅读 
 
I'm trying convert my list to dictionary in python. I have list l 
l = ['a', 'b', 'c', 'd']
and I want convert it to dictionary d
d['a'] = []
d['b'] = []
d['c'] = []
d['d'] = []
I was trying 
for i in range(0, len(l)):
    d[i][0]=l(i)
but that don't work. Thanks
 解决方案 
Keep it a bit simpler than that, you want to loop over your list, and then assign your iterator i (which will be each value in your list) as the key to each dictionary entry. 
l = ['a', 'b', 'c', 'd']

d = {}
for i in l:
    d[i] = []


print(d) # {'a': [], 'c': [], 'b': [], 'd': []}
With the above understood, you can now actually simplify this in to one line as: 
{k: [] for k in l}
The above is called a dictionary comprehension. You can read about it here
                        
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