问题描述
我收到此错误
尝试执行此操作
//DB query
$stmt = $con->prepare("SELECT token_created_at from reset WHERE token = :urltoken");
$stmt->bindValue(':urltoken', $_GET['token']);
$stmt->execute();
$stmt->setFetchMode(PDO::FETCH_ASSOC);
while($row = $stmt->fetch()) {
$token_created_at = $row['token_created_at'];
}
//Remove after testing
echo $token_created_at;
$my_dt = new DateTime($token_created_at);
//Modify error
$expires_at = $my_dt->modify('+1 hour');
//Return current time to match
$current_time = date('m-d-Y H:i:s ', time());
第17行是$my_dt = new DateTime($token_created_at);
,这是我的时间格式06-28-2014 07:43:58
.
Line 17 is $my_dt = new DateTime($token_created_at);
and this is my time format 06-28-2014 07:43:58
.
这就是我生成token_created_at
,$time_gen = date('m-d-Y H:i:s ', time());
的方式.
This is how I generate token_created_at
, $time_gen = date('m-d-Y H:i:s ', time());
.
推荐答案
您传递的日期字符串为 .您必须使用 createFromFormat 创建DateTime对象.此方法允许您在创建新的DateTime对象时指定自定义格式:
The date string you're passing is not supported by the DateTime parser. You must create a DateTime object by using createFromFormat. This method allows you to specify the custom format when creating a new DateTime object:
$my_dt = DateTime::createFromFormat('m-d-Y H:i:s', $token_created_at);
如果仍然出现错误,则表明您的$token_created_at
格式不符合您指定的格式:
If you're still getting an error that means that your $token_created_at
is not in the format you specified:
$now = date('m-d-Y H:i:s'); //string(19) "06-28-2014 15:00:47"
var_dump(DateTime::createFromFormat('m-d-Y H:i:s', $now));
object(DateTime)#1 (3) {
["date"]=>
string(19) "2014-06-28 15:00:47"
["timezone_type"]=>
int(3)
["timezone"]=>
string(13) "Europe/Berlin"
}
修改
我看到了您的问题-s
后面的格式字符串有一个空格.格式字符串必须完全匹配 :
I see your problem - the format string has a space after s
. The format strings must match exactly:
$my_dt = DateTime::createFromFormat('m-d-Y H:i:s ', $token_created_at);
这篇关于致命错误:消息为"DateTime :: __ construct()的未捕获异常" Exception":无法解析时间字符串的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!