问题描述
我使用 scikit-learn 在 python 中创建了一个自定义模型,我想使用交叉验证.
I have created a custom model in python using scikit-learn, and I want to use cross validation.
模型的类定义如下:
class MultiLabelEnsemble:
''' MultiLabelEnsemble(predictorInstance, balance=False)
Like OneVsRestClassifier: Wrapping class to train multiple models when
several objectives are given as target values. Its predictor may be an ensemble.
This class can be used to create a one-vs-rest classifier from multiple 0/1 labels
to treat a multi-label problem or to create a one-vs-rest classifier from
a categorical target variable.
Arguments:
predictorInstance -- A predictor instance is passed as argument (be careful, you must instantiate
the predictor class before passing the argument, i.e. end with (),
e.g. LogisticRegression().
balance -- True/False. If True, attempts to re-balance classes in training data
by including a random sample (without replacement) s.t. the largest class has at most 2 times
the number of elements of the smallest one.
Example Usage: mymodel = MultiLabelEnsemble (GradientBoostingClassifier(), True)'''
def __init__(self, predictorInstance, balance=False):
self.predictors = [predictorInstance]
self.n_label = 1
self.n_target = 1
self.n_estimators = 1 # for predictors that are ensembles of estimators
self.balance=balance
def __repr__(self):
return "MultiLabelEnsemble"
def __str__(self):
return "MultiLabelEnsemble :
" + " n_label={}
".format(self.n_label) + " n_target={}
".format(self.n_target) + " n_estimators={}
".format(self.n_estimators) + str(self.predictors[0])
def fit(self, Xtrain, Ytrain):
if len(Ytrain.shape)==1:
Ytrain = np.array([Ytrain]).transpose() # Transform vector into column matrix
# This is NOT what we want: Y = Y.reshape( -1, 1 ), because Y.shape[1] out of range
self.n_target = Ytrain.shape[1] # Num target values = num col of Y
self.n_label = len(set(Ytrain.ravel())) # Num labels = num classes (categories of categorical var if n_target=1 or n_target if labels are binary )
# Create the right number of copies of the predictor instance
if len(self.predictors)!=self.n_target:
predictorInstance = self.predictors[0]
self.predictors = [predictorInstance]
for i in range(1,self.n_target):
self.predictors.append(copy.copy(predictorInstance))
# Fit all predictors
for i in range(self.n_target):
# Update the number of desired prodictos
if hasattr(self.predictors[i], 'n_estimators'):
self.predictors[i].n_estimators=self.n_estimators
# Subsample if desired
if self.balance:
pos = Ytrain[:,i]>0
neg = Ytrain[:,i]<=0
if sum(pos)<sum(neg):
chosen = pos
not_chosen = neg
else:
chosen = neg
not_chosen = pos
num = sum(chosen)
idx=filter(lambda(x): x[1]==True, enumerate(not_chosen))
idx=np.array(zip(*idx)[0])
np.random.shuffle(idx)
chosen[idx[0:min(num, len(idx))]]=True
# Train with chosen samples
self.predictors[i].fit(Xtrain[chosen,:],Ytrain[chosen,i])
else:
self.predictors[i].fit(Xtrain,Ytrain[:,i])
return
def predict_proba(self, Xtrain):
if len(Xtrain.shape)==1: # IG modif Feb3 2015
X = np.reshape(Xtrain,(-1,1))
prediction = self.predictors[0].predict_proba(Xtrain)
if self.n_label==2: # Keep only 1 prediction, 1st column = (1 - 2nd column)
prediction = prediction[:,1]
for i in range(1,self.n_target): # More than 1 target, we assume that labels are binary
new_prediction = self.predictors[i].predict_proba(Xtrain)[:,1]
prediction = np.column_stack((prediction, new_prediction))
return prediction
当我像这样调用这个类进行交叉验证时:
When I call this class for cross validation like this:
kf = cross_validation.KFold(len(Xtrain), n_folds=10)
score = cross_val_score(self.model, Xtrain, Ytrain, cv=kf, n_jobs=-1).mean()
我收到以下错误:
TypeError:如果未指定评分,则传递的估算器应具有评分"方法.估计器 MultiLabelEnsemble 没有.
TypeError: If no scoring is specified, the estimator passed should have a 'score' method. The estimator MultiLabelEnsemble does not.
如何创建评分方法?
推荐答案
使错误消失的最简单方法是通过 scoring="accuracy"
或 scoring="hamming"
到 cross_val_score
.cross_val_score
函数本身不知道您要解决什么样的问题,因此它不知道合适的度量标准是什么.看起来您正在尝试进行多标签分类,所以您想使用汉明损失吗?
The easiest way to make the error go away is to pass scoring="accuracy"
or scoring="hamming"
to cross_val_score
. The cross_val_score
function itself doesn't know what kind of problem you are trying to solve, so it doesn't know what an appropriate metric is. It looks like you are trying to do multi-label classification, so maybe you want to use the hamming loss?
您还可以实现一个 score
方法,如滚动您自己的估算器"文档中所述,其具有作为签名def score(self, X, y_true)
.参见 http://scikit-learn.org/stable/developers/#different-objects
You can also implement a score
method as explained in the "Roll your own estimator" docs, which has as signaturedef score(self, X, y_true)
. See http://scikit-learn.org/stable/developers/#different-objects
顺便说一下,您确实了解 OneVsRestClassifier
,对吗?看起来有点像您正在重新实现它.
By the way, you do know about the OneVsRestClassifier
, right? It looks a bit like you are reimplementing it.
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