本文介绍了如何在php中获取图像类型的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我正在尝试获取数据库中的图像类型,但以下内容不起作用.如何检测图像是png,jpeg还是gif?
I am trying to get the image type in the database but the below isn't working. How do I detect if the image is png, jpeg or gif?
if(isset($_POST['submit'])) {
$fileType = $_FILES['image']['type'];
$tmpname = $_FILES['image']['tmp_name'];
$fp = fopen($tmpname,'r');
$data = fread($fp,filesize($tmpname));
$data = addslashes($data);
fclose($fp);
$update = mysql_query("UPDATE avatar SET image1='$data',type='$fileType' WHERE username='$user'",$this->connect);
} else {
echo "<form enctype='multipart/form-data' action='http://www.example.com/cp/avatar' method='post'>
<div id='afield1' >Upload</div><div id='afield2'><input type='hidden' name='MAX_FILE_SIZE' value='102400' /><input type='file' size='25' name='image' /></div>
<div id='asubmit'><input type='submit' name='submit' class='button' value='Save Changes' /></div>
</form>";
}
推荐答案
使用 getimagesize()或 exif_imagetype()
// integer - for example: IMAGETYPE_GIF, IMAGETYPE_JPEG etc.
$type = exif_imagetype($_FILES['image']['tmp_name']);
和
$info = getimagesize($_FILES['image']['tmp_name']);
$mime = $info['mime']; // mime-type as string for ex. "image/jpeg" etc.
$width = $info[0]; // width as integer for ex. 512
$height = $info[1]; // height as integer for ex. 384
$type = $info[2]; // same as exif_imagetype
请注意,exif_imagetype
比getimagesize
快得多.查看文档以获取更多信息.
Mind that exif_imagetype
is much faster than getimagesize
. Check documentation for more info.
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