问题描述
我有一个具有通用关系的模型:
I have a model with a generic relation:
TrackedItem --- genericrelation ---> any model
我希望能够从初始模型中获得跟踪的项目.
I would like to be able to generically get, from the initial model, the tracked item.
我应该能够在不修改任何模型的情况下做到这一点.
I should be able to do it on any model without modifying it.
为此，我需要获取内容类型和对象 ID.获取对象 id 很容易，因为我有模型实例，但获取内容类型不是:ContentType.object.filter 需要模型(它只是 content_object.__class__.__name__)和 app_label.
To do that I need to get the content type and the object id. Getting the object id is easy since I have the model instance, but getting the content type is not: ContentType.object.filter requires the model (which is just content_object.__class__.__name__) and the app_label.
我不知道如何以可靠的方式获取模型所在的应用程序.
I have no idea of how to get in a reliable way the app in which a model is.
现在我做 app = content_object.__module__.split(".")[0]，但它不适用于 django contrib 应用程序.
For now I do app = content_object.__module__.split(".")[0], but it doesn't work with django contrib apps.
推荐答案
您不需要为了获取内容类型而获取应用程序或模型 - 有一个方便的方法可以做到这一点:
You don't need to get the app or model just to get the contenttype - there's a handy method to do just that:
from django.contrib.contenttypes.models import ContentType
ContentType.objects.get_for_model(myobject)
尽管名称如此，但它适用于模型类和实例.
Despite the name, it works for both model classes and instances.
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