PHP的foreach数组对象stdClass已经

问题描述

我需要帮助想进去阵列和stdClass的对象值。

FYI：我使用Foursquare的API ...

我有这样的事情：

 `$ fsq_groups = $ venues-＆GT;响应 - 基团;`    回声＆LT; pre＆gt;中;
    的print_r（$ fsq_groups）;
    回声＆LT; / pre＆gt;中;
 

从的print_r（$ fsq_groups）;

 阵列
（
    [0] =＆GT; stdClass的对象
        （
            [类型] = GT;推荐地点
            [名] =＆GT;推荐的
            [项目] =＆GT;排列
                （
                    [0] =＆GT; stdClass的对象
                        （
                            [原因] =＆GT; stdClass的对象
                                （
                                    [计] =＆GT; 2
                                    [项目] =＆GT;排列
                                        （
                                            [0] =＆GT; stdClass的对象
                                                （
                                                    [类型] = GT;一般
                                                    [消息] =＆GT;很多人都提到的汉堡包在这里
                                                ）                                            [1] =＆GT; stdClass的对象
                                                （
                                                    [类型] = GT;一般
                                                    [消息] =＆GT;这点是Foursquare的流行
                                                ）                                        ）                                ）                            [地点] =＆GT; stdClass的对象
                                （
                                    [ID] =＆GT; 4afe5a4bf964a520372f22e3
                                    [名] =＆GT;粗壮的汉堡和放大器;啤酒
                                    [联系方式] =＆GT; stdClass的对象
...
 

我怎么到名称在地点

我想这样的事情，但没有工作：

 的foreach（$ fsq_groups为$组）
{
    的foreach（$组 - ＆GT;＆物品─GT;场地为$场地）
    {            回声$ venue-＆GT;名;
                回声＆LT; pre＆gt;中;
                的print_r（$场地）;
                回声＆LT; / pre＆gt;中;
    }
}
 

解决方案

  $ fsq_groups = $ venues-＆GT;响应 - 基团;
如果（使用isset（$ fsq_groups [0]））{
    $组= $ fsq_groups [0];
    的foreach（$组 - ＆GT;项目为$关键=＆GT; $的地方）{
        $场地= $占位＆GT;地点;
        回声$ venue-＆GT;名;
    }
}
 

I need help trying to get values inside array and stdClass Object.

FYI: I'm using foursquare API...

I have something like this:

`$fsq_groups = $venues->response->groups;`

    echo "<pre>";
    print_r($fsq_groups);
    echo "</pre>";

From print_r($fsq_groups);

Array
(
    [0] => stdClass Object
        (
            [type] => Recommended Places
            [name] => recommended
            [items] => Array
                (
                    [0] => stdClass Object
                        (
                            [reasons] => stdClass Object
                                (
                                    [count] => 2
                                    [items] => Array
                                        (
                                            [0] => stdClass Object
                                                (
                                                    [type] => general
                                                    [message] => Lots of people have mentioned "burgers" here
                                                )

                                            [1] => stdClass Object
                                                (
                                                    [type] => general
                                                    [message] => This spot is popular on Foursquare
                                                )

                                        )

                                )

                            [venue] => stdClass Object
                                (
                                    [id] => 4afe5a4bf964a520372f22e3
                                    [name] => Stout Burgers & Beer
                                    [contact] => stdClass Object
...

How do I get to the name under venue

I tried something like this but didn't work:

foreach($fsq_groups as $groups)
{
    foreach($groups->items->venue as $venue)
    {

            echo $venue->name;
                echo "<pre>";
                print_r($venue);
                echo "</pre>";
    }
}

解决方案

$fsq_groups = $venues->response->groups;
if(isset($fsq_groups[0])){
    $groups = $fsq_groups[0];
    foreach($groups->items as $key => $place){
        $venue = $place->venue;
        echo $venue->name;
    }
}

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