本文介绍了Python:列表列表的唯一性的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！
问题描述
我很好奇什么是唯一化此类数据对象的有效方法:
I am curious what would be an efficient way of uniquefying such data objects:
testdata =[ ['9034968', 'ETH'], ['14160113', 'ETH'], ['9034968', 'ETH'], ['11111', 'NOT'], ['9555269', 'NOT'], ['15724032', 'ETH'], ['15481740', 'ETH'], ['15481757', 'ETH'], ['15481724', 'ETH'], ['10307528', 'ETH'], ['15481757', 'ETH'], ['15481724', 'ETH'], ['15481740', 'ETH'], ['15379365', 'ETH'], ['11111', 'NOT'], ['9555269', 'NOT'], ['15379365', 'ETH']
]
对于每个数据对，左边的数字字符串加上右边的类型表示数据元素的唯一性.返回值应该是与测试数据相同的列表列表，但只保留唯一值.
For each data pair, left numeric string PLUS the type at the right tells the uniqueness of a data element. The return value should be a list of lists as same as the testdata, but with only the unique values kept.
推荐答案
您可以使用一组:
unique_data = [list(x) for x in set(tuple(x) for x in testdata)]
您还可以查看 此页面，其中对各种方法进行了基准测试，这些方法要么保留或不保留顺序.
You can also see this page which benchmarks a variety of methods that either preserve or don't preserve order.
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