问题描述
根据我的教科书,L1的补语= A *-只要L1是常规语言,L1就是常规语言。
A *不包括上下文无关的语言,上下文敏感语言和递归枚举语言? A * -L1也将包括所有这些,不是吗?
在有限状态机的表示下,我理解为什么补语仍然是常规语言。但是,我无法理解其背后的理论。
According to my textbook, the complement of L1 = A* - L1 is a regular language as long as L1 is a regular language.
Doesn't A* also include Context Free languages, Context Sensitive languages, and Recursively Enumerable languages? A*-L1 would include all of them too, wouldn't it? How can it be regular then?
Under the representation of a Finite State Machine I understand why the complement is still a regular language. However, I can't understand the theory behind it.
此外,A *-L1 = A *交集补(L1)。用补语定义的重语不是用补语来定义补语吗?我真的不明白这怎么可能有效。
Also, A* - L1 = A* intersection complement(L1) . Isn't defining a complement with something defined by the complement a tautology? I don't really understand how that can be valid.
谢谢。
推荐答案
我认为您感到困惑的是,当您说 A *
还不包括上下文无关语言,上下文敏感语言和递归可枚举语言吗?您会混淆一组字符串的 A *
和 Powerset(A *)
,这是一组语言。
I think where you are confused is that when you say "Doesn't A*
also include Context Free languages, Context Sensitive languages, and Recursively Enumerable languages?" you are confusing A*
, which is a set of strings, with Powerset(A*)
, which is a set of languages.
确实, Powerset(A *)-{L1 }
是一个包含上下文无关的语言,上下文敏感的语言和递归可枚举的语言的集合,但它实际上与定理无关,后者只是说:给定任何常规语言 L
(一组字符串),则语言 A * -L
也是一组字符串
It is true that Powerset(A*) - {L1}
is a set containing "Context Free languages, Context Sensitive languages, and Recursively Enumerable languages" but it actually isn't relevant to the theorem which just says: given any regular language L
(a set of strings), then the language A*-L
, also a set of strings, is also a regular language.
TL;在您的问题中,各个级别之间存在混淆:字符串集与语言集。 A *
分为 L
和 A * -L $ c的任何两个分区其中
L
是常规的$ c>还必须具有 A * -L
常规。 A *
不能并且不能包含语言,因为它是一组字符串。
TL;DR there's a confusion between levels in your question: sets of strings vs. sets of languages. Any two-partition of A*
into L
and A*-L
in which L
is regular must also have A*-L
regular. A*
does not and cannot "contain languages" because it is a set of strings.
第二个问题:
好问题。我怀疑这是否表示为定义,即仅定义运算符-
。据我所知,它没有定义补码功能。也许已经定义了补码,并且您的书现在正在尝试定义减法运算符。否则,这是一个定理,而不是定义。
Nice question. I suspect if this is presented as a definition, that is just defining operator -
. It is not defining the "complement function" as far as I can tell. Perhaps "complement" was already defined, and your book is now trying to define the subtraction operator. Or else this is a theorem rather than a definition.
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